Answer:
-5/2
Step-by-step explanation:
Slope m = (y2-y1)/(x2-x1)
m = (-2 - 8)/(6 - 2) = -10/4 = -5/2
so y = mx + b
y = -5/2x + b
Using (2,8)
8 = -5/2(2) + b
8 = -5 + b
b = 13
then y = -5/2x + 13
Answer: I think it goes like this im pretty sure ;)
Distribute
q+12-2q+44>0
Combine like terms
-q+56>0
Subtract 56 from both sides
-q>-56
Multiply both sides by -1 (flip the inequality sign)
q<56
The Final answer: q<56
Prove
m∠5+m∠2+m∠6=180°
we have that
m∠1+m∠2+m∠3=180° equation I
m∠1=m∠5 -------- > in<span>ternal alternate angles equation 2
</span>
and
m∠6=m∠3-------- > internal alternate angles equation 3
<span>I substitute equation 2 and equation 3 in equation I</span>
m∠1+m∠2+m∠3=180°-------- > m∠5+m∠2+m∠6=180°------- > is ok
