All categories

3 years ago

Today, everything in the store is on sale. The store offers a 20% discount.

Mathematics

1 answer:

nadezda [96]3 years ago

3 0

A) The regular price of a t-shirt is $18. What is the discount price?

$14.4

B) Which equation represents this problem?

a) y = 0.8x b) y = 0.2x c) y = 1.80x d) y = 1.20x

The answer would be B.

C) The discount price of a hat is $18. What is the regular price?

22.5

<u>Hope it helped!! ^^ </u>

<u>Note: if you need me to explain i Would be happy to do so! :)</u>

You might be interested in

Please help ?????????

Murrr4er [49]

Answer:

B is your answer to this problem

Step-by-step explanation:

4 0

3 years ago

I need help on my homework here it is <br> Solve the equation for x.<br><br><br> x3 = 64/343

nordsb [41]

x^3 = 64/343

x^3 = 4^3 / 7^3

x = ∛(4^3 / 7^3)

x = ∛4^3 / ∛7^3

x = 4/7

3 0

3 years ago

PLZ HELP ME QUICKLY!!!!!!!!!!

BARSIC [14]

(1/3) bag = (1/4) lb.
multiply by 3 on both sides to get 1 full bag.
3(1/3)b = 3(1/4)
1 bag = (3/4) lb.

3 0

3 years ago

One gram of protein contains 4 calories. One gram of fat contains 9 calories. A snack has 60 calories from p grams of protein an

nikitadnepr [17]

Answer:

1.5 grams of protein.

Step-by-step explanation:

The equation that represents the relationship between protein and fat is as follows :

4p + 9f = 60 ....(1)

We need to find the grams of protein are there if there are 6 grams of fat in the snack.

Put f = 6 in the above equation (1).

4p + 9(6)= 60

4p + 54 = 60

Subtract 54 to the both sides,

4p + 54-54 = 60-54

4p = 6

⇒ p = 1.5 grams

It means the snack contains 1.5 grams of protein.

4 0

3 years ago

How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the

miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

$\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}$

___

$\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}$

___

$\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}$

Neither solution makes any denominator be zero, so both are good solutions.

8 0

3 years ago