Answer:
Part a) 
Part b) 
Step-by-step explanation:
Part a)
Let
x -----> the number of weeks
y ----> the total amount Chem has deposited in a saving account
we know that
The equation of a line in slope intercept form is

where
m is the rate or slope of the linear equation
b is the y-intercept of the linear equation or initial value (value of y when the value of x is equal to zero)
In this problem we have that
The rate or slope is equal to
-----> amount deposited by Chem each week
The y-intercept or initial value is
----> amount deposited originally in the saving account
substitute the values

Part b) How much has Chem deposited 30 weeks after his initial deposit?
For x=30 weeks
substitute in the equation


Answer:
Step-by-step explanation:
Given that f(x) = 3x + 21
Plug in 3 for x
F(3)= 3(3) +21
F(3) = 9+21
f(3) = 30
Plug in 7 for x
F(7)= 3(7) +21
F(7) = 21+21
f(7) = 42
Answer: 6 horses bc you just have to multiply by 3
Answer:
26
Step-by-step explanation:
sub it it
50-(4×6)
50-24