All categories

2 years ago

Find the mode of the following data set: 18,17,12,14,8,21,10,11,19,20,5,17,12,10,20

Mathematics

2 answers:

dem82 [27]2 years ago

3 0

Answer:

C.10

Step-by-step explanation:

it is the only number that appeared most times

hammer [34]2 years ago

3 0

C- 10

Mode- The number that a occurs is a set of data the Most.

In the set you have

no 16's One 14 2 tens and no 13's

You might be interested in

What is the volume of the prism

almond37 [142]

The volume of a rectangular prism or cube is: Length × Width × Height

In this case,

- the length of the prism is 2 feet

- the width of the prism is 1.5 feet

- the height of the prism is 1.5 feet

Multiply the above to find the volume: 2 × 1.5 × 1.5 = 4.5 ft³

Keep in mind that volume is represented in cubic units!

4 0

3 years ago

Read 2 more answers

Which equation has the same solution as 2x^2+16x-10=0

dmitriy555 [2]

D
Divide the whole thing by 2
2(X^2+8x-5)
X^2+8x. =5
Half of 8 is 4 sq it so you add 16
X^2+8x+16= 5+16
(X+4)^2=21

8 0

2 years ago

Read 2 more answers

Without multiplying, determine the sign of the product (356,864)(−194,758).

STatiana [176]

I think it would be A.) but at the same time i think it's wrong

8 0

3 years ago

Read 2 more answers

Simplify the expression. Assume all variables are positive. (r/32s)^8/5

balandron [24]

Answer:

Step-by-step explanation:

Alright, lets get started.

The given expression is :

$(\frac{r}{32s} )^{\frac{8}{5} }$

It could be written as

$(\frac{r}{s} )^{\frac{8}{5} }*(\frac{1}{32} )^{\frac{8}{5} }$

32 could be written as $2^{5}$

So, replacing that in our expression

$(\frac{r}{s} )^{\frac{8}{5} }*(\frac{1}{2^{5} } )^{\frac{8}{5} }$

$(\frac{r}{s} )^{\frac{8}{5} }*(\frac{1}{2} )^{5*\frac{8}{5} }$

$(\frac{r}{s} )^{\frac{8}{5} }*(\frac{1}{2} )^{8}$

$\frac{1}{256}*(\frac{r}{s} )^{\frac{8}{5} }$

This is the simplified form of given expression. : Answer

Hope it will help :)

6 0

2 years ago

One vegetable warehouse had 210 tons of potatoes, another one had 180 tons. 90 tons of potatoes were delivered to the first and

kow [346]

Answer:

The number of days in which the amount in warehouse #2 is 1.2 greater than warehouse #1 is 6 days.

Step-by-step explanation:

Let

x: number of days

y: amount of potatoes

We can express the amount of potatoes in each warehouse using linear equations:

Warehouse #1: $y_1 = 90x+210$

Warehouse #2: $y_2 = 120x+180$

We need to find the value of x when $1.2*y_{1} =y_{2}$

Substituting the expressions for y1 and y2 in $1.2*y_{1} =y_{2}$ :

$1.2*(90x+210) =120x+180$

Applying distributive law:

$108x+252 =120x+180$

Solving the equation by subtracting 108x and 180 on both sides:

$108x+252-108x-180 =120x+180-108x-180$

$252-180 =120x-108x$

$72 =12x$

Now we divide by 12 on both sides:

$\frac{72}{12} =\frac{12x}{12}\\6=x\\x=6$

Therefore, the number of days in which the amount in warehouse #2 is 1.2 greater than warehouse #1 is 6 days.

4 0

3 years ago