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3 years ago

Find the approximate length of segment AC. Math item stem image CLEAR CHECK 5.74 units 8.06 units 11 units 65 units

Mathematics

1 answer:

laiz [17]3 years ago

8 0

Answer:

$\large\boxed{\large\boxed{8.06units}}$

Explanation:

The figure is a right triangle with:

hypotenuse = segment AC
vertical leg = 7 units
horizontal leg = 4 units

Hence, you must use Pythagora's theorem, which is valid for all right triangles:

$hypotenuse^2=(leg_1)^2+(leg_2)^2$

Substituting the data:

$hypotenuse^2=(7unit)^2+(4unit)^2=49unit^2+16unit^2=65unit^2$

Square root both sides:

$hypotenuse=\sqrt{65unit^2}=8.06unit$

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Partially factored form: f(x) = (x − 3)(x 3)(x2− 4x 5) use the quadratic formula to identify the zeroes of x2 − 4x 5. x =

Dimas [21]

Answer:

2 ± i

Step-by-step explanation:

by 5, I assume you mean +5

x² - 4x + 5 = 0

x = (-b±(√(b²-4ac)) / 2a

x = (4 ± (√(16 - 20)) / 2

x = (4 ± (√(-4)) / 2

√-4 = √4√-1 which is 2i

x = (4 ± 2i) / 2

x = 2 ± i

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2 years ago

A restaurant has 40 tables in its dining room. It takes the

SVETLANKA909090 [29]

40 tables, 4 tables per 12 minutes so 40/4*12 which would be 120 minutes.

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2 years ago

Help ?!-10+3x=8 <br> X=??

jekas [21]

Ok, so first off you need to remember that your goal is to get x alone.
How do you do this? Well, let's get rid of that pesky negative ten, shall we?
The opposite of a negative is positive, so you can move negative ten to the other side of the problem by adding ten. Make sure that you do operations on both sides. Once you add, you have 3x=18. When a number is right next door to an x, it means it is being multiplied. To get rid of the three, divide by three on both sides. Now your get x=6, which is your answer. Hopefully, I explained this well! :D

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2 years ago

Read 2 more answers

Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.

grandymaker [24]

$(2x+1)^{\cot x}=\exp\left(\ln(2x+1)^{\cot x}\right)=\exp\left(\cot x\ln(2x+1)\right)=\exp\left(\dfrac{\ln(2x+1)}{\tan x}\right)$

where $\exp(x)\equiv e^x$ .

By continuity of $e^x$ , you have

$\displaystyle\lim_{x\to0^+}\exp\left(\dfrac{\ln(2x+1)}{\tan x}\right)=\exp\left(\lim_{x\to0^+}\dfrac{\ln(2x+1)}{\tan x}\right)$

As $x\to0^+$ in the numerator, you approach $\ln1=0$ ; in the denominator, you approach $\tan0=0$ . So you have an indeterminate form $\dfrac00$ . Provided the limit indeed exists, L'Hopital's rule can be used.

$\displaystyle\exp\left(\lim_{x\to0^+}\dfrac{\ln(2x+1)}{\tan x}\right)=\exp\left(\lim_{x\to0^+}\dfrac{\frac2{2x+1}}{\sec^2x}\right)$

Now the numerator approaches $\dfrac21=2$ , while the denominator approaches $\sec^20=1$ , suggesting the limit above is 2. This means

$\displaystyle\lim_{x\to0^+}(2x+1)^{\cot x}=\exp(2)=e^2$

7 0

2 years ago

1 -For what value of x is line a parallel to line b

IgorC [24]

Answer:

1) x = 17, line a parallel to line b

2) x = 18, line a parallel to line b

Step-by-step explanation:

If line a parallel to line b then (10x - 40) + 50 = 180

Solve for x

10x - 40 + 50 = 180

Combine like terms

10x + 10 = 180

10x = 170

x = 17

x = 17, line a parallel to line b

-------------------------------------------------

If line a parallel to line b then 5x - 16 = 74

Solve for x

5x - 16 = 74

5x = 90

x = 18

x = 18, line a parallel to line b

4 0

3 years ago