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Arte-miy333 [17]
3 years ago
6

At Jefferson Middle School, eighty-two students were asked which sports they plan to participate in for the coming year. Twenty

students plan to participate in track and cross country; six students in cross country and basketball; and eight students in track and basketball. Twelve students plan to participate in all three sports. A total of thirty students plan to participate in basketball, and a total of forty students plan to participate in cross country. Ten students don't plan to participate in any of the three sports. How many students plan to just participate in track? 40 60 20 30
Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
7 0

Answer: C :20

Step-by-step explanation:

Lana71 [14]3 years ago
3 0
I believe it would be 20
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PLEASE HELP ME!!Write the quotient as a mixed number.<br> 46 divided by 9 = 5 R1
Zigmanuir [339]

Answer:

5\frac{1}{9}

Step-by-step explanation:

When dividing 46 by 9 quotient is 5 and remainder is 46 - 45 = 1

5\frac{1}{9}

5 0
3 years ago
How to find the value of x 103-4x=71
jasenka [17]

Answer:

x= 8

Step-by-step explanation:

103 - 4x = 71

You have to isolate -4x by using the subtraction property of equality on 103

103(-103) -4x = 71(-103)

-4x = -32

Use Multiplication Property of Equality for the negative

4x = 32

Divide 4 from both sides

x= 8

3 0
3 years ago
Ff is a trigonometric function of the form f(x)=a\sin(bx+c)+df(x)=asin(bx+c)+df, left parenthesis, x, right parenthesis, equals,
andriy [413]

The <em>trigonometric</em> function that represents the curve seen in the picture is f(x) = 4.5 · sin (π · x / 2 - π) - 6.5.

<h3>How to derive a sinusoidal expression</h3>

In this problem we need to find a <em>sinusoidal</em> expression that models the curve seen in the picture. The most typical <em>sinusoidal</em> model is described below:

f(x) = a · sin (b · x + c) + d    (1)

Where:

  • a - Amplitude
  • b - Angular frequency
  • c - Angular phase
  • d - Vertical midpoint

Now we proceed to find the value of each variable:

Amplitude

a = - 2 - (-6.5)

a = 4.5

Angular frequency

b = 2π / T, where T is the period.

0.25 · T = 4 - 3

T = 4

b = 2π / 4

b = π / 2

Midpoint

d = - 6.5

Angular phase

- 2 = 4.5 · sin (π · 4/2 + c) - 6.5

4.5 = 4.5 · sin (π · 4/2 + c)

1 = sin (2π + c)

π = 2π + c

c = - π

The <em>trigonometric</em> function that represents the curve seen in the picture is f(x) = 4.5 · sin (π · x / 2 - π) - 6.5.

To learn more on trigonometric functions: brainly.com/question/15706158

#SPJ1

3 0
2 years ago
Find the length of the diameter of circle 0
r-ruslan [8.4K]

Answer:

Diameter = 19.33

Step-by-step explanation:

Imaging a radius line from O to the endpoints of the 7. call this line R.

Label the part of the vertical line from O to the 90 degree intersection y.

Now you have a right triangle.

Using the Pythagorean theorem:

R² = 7² + y²

also

y = R - 3

substitute for y:

R² = 49 + (R-3)²

R² = 49 + R² - 6R + 9

simplify:

0 = 58 - 6R

6R = 58

R = 9.6667

Diameter = 2(9.6667) = 19.33

5 0
2 years ago
Find the angle [OA] makes with the positive x-axis if the x-coordinate of the point A on the unit circle is 0.222
EastWind [94]

By using the concepts of <em>unit</em> circle and <em>trigonometric</em> functions, we find that the angle OA, whose x-coordinate is 0.222, has a measure of approximately 77.173°.

<h3>How to find an angle in an unit circle</h3>

<em>Unit</em> circles are circles with radius of 1 and centered at the origin of a Cartesian plane, which are used to determine angles and <em>trigonometric</em> functions related to them. If we use <em>rectangular</em> coordinate system and the definition of the <em>tangent</em> function, we find that the angle OA is equal to:

\tan \theta = \frac{\sqrt{1 - x^{2}}}{x}

\tan \theta = \frac{\sqrt{1-0.222^{2}}}{0.222}

tan θ ≈ 77.173°

By using the concepts of <em>unit</em> circle and <em>trigonometric</em> functions, we find that the angle OA, whose x-coordinate is 0.222, has a measure of approximately 77.173°.

To learn more on unit circles: brainly.com/question/12100731

#SPJ1

4 0
2 years ago
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