Question

In ΔABC, ∠CAD = 22° and segment CB = 15 cm. If the cos of 22° = 0.9272, then the sin of ∠C = _______.

Answer 1

Answer:

Step-by-step explanation:

In the given triangle ABC, ∠CAD = 22° segment CB = 15 cm.

We have to find sin of ∠C.

In the given triangle ADC,

∠CAD + ∠ADC + ∠DCA = 180

22° + 90° + ∠DCA = 180

∠DCA = 180 - 112 = 68°

Now we have to get the value of sinC or sin of angle DCA

Therefore sinC = sin 68° = 0.9272

Option B. 0.9272 is the correct option.

Answer 2

You can calculate $\sin22^{\circ}$ using formula:
$\cos^222^{\circ}+\sin^222^{\circ}=1$.
Then $\sin^222^{\circ}=1-\cos^222^{\circ}$ and
$\sin^222^{\circ}=1-( 0.9272)^2=0.14030016 \\ \sin22^{\circ}= \sqrt{0.14030016} =0.3746$.
Answer: $\sin22^{\circ}=0.3746$