Can yall help me with this pls its due rn and im cryinggggg ill definetly give brainliesttt : (
2 answers:
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Answer:
Answer for the question :
A resercher is wondering whehter the drinking habits of adults in a certain region of the country are in the same proportion as the general population of adults. Suppose a recent study stated that the proportion of adults who reported drinking once a week or less in the last month was 0.26. The researcher's null hypothesis for this test is H0: P=0.26 and the alternative hypothesis is Ha; P> 0.26. The researcher collected datat from a random sample of 75 adults in the region of interest.
1- Verify that the normality assumption is satisfied. Describe each separately.
2- To cotinue the study into the drinking habits of adults, the researcher decides to collect datat from adults working in "blue collar" jobs to see whether their drinking habits are in the same proportion as the general public. The null hypothesis for this test is H0: P=0.26 and the alternative hypothesis is Ha: P>0.26. The researcher computer the test statistic to be 1.59. Draw a graph of z distribution, label the test statistic and shade the p-value associated with this test statistic."
is given in the attachment.
Step-by-step explanation:
Answer:
The fraction of the students who failed to went partying =
Step-by-step explanation:
Let total number of students = 100
No. of students partied are twice the no. of students who not partied.
⇒ No. of students partied = 2 × the no. of students who are not partied
No. of students partied before the exam = 20 % of total students
⇒ No. of students partied before the exam = × 100
⇒ No. of students partied before the exam = 20
No. of students who not partied before the exam =
Thus the fraction of the students who failed to went partying =