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larisa86 [58]
3 years ago
13

Write a linear equation in standard form given the line passes through (-4,-3) and (6,-2).

Mathematics
1 answer:
garik1379 [7]3 years ago
7 0
(-2+3)/(6+4)= 1/10

y+3=1/10(x + 4)

y + 3 = (1/10)x + 4/10

y + 30/10 = ( 1/10)x + 4/10

y = (1/10)x + 4/10 - 30/10

y = (1/10)x - 26/10

y = (1/10)x - 13/5

10(y = (1/10)x - 13/5)

10y = x - 26

-x + 10y = -26

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Answer:

-6.95 x 10^10

Step-by-step explanation:

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3 years ago
The Mountain View ski resort kept track of the number of visitors they had each weekend during their busy season. This box plot
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Step-by-step explanation:

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Read 2 more answers
What is the sum of the first 37 terms of the arithmetic sequence?
lidiya [134]

Answer:

The sum of the first 37 terms of the arithmetic sequence is 2997.

Step-by-step explanation:

Arithmetic sequence concepts:

The general rule of an arithmetic sequence is the following:

a_{n+1} = a_{n} + d

In which d is the common diference between each term.

We can expand the general equation to find the nth term from the first, by the following equation:

a_{n} = a_{1} + (n-1)*d

The sum of the first n terms of an arithmetic sequence is given by:

S_{n} = \frac{n(a_{1} + a_{n})}{2}

In this question:

a_{1} = -27, d = -21 - (-27) = -15 - (-21) = ... = 6

We want the sum of the first 37 terms, so we have to find a_{37}

a_{n} = a_{1} + (n-1)*d

a_{37} = a_{1} + (36)*d

a_{37} = -27 + 36*6

a_{37} = 189

Then

S_{37} = \frac{37(-27 + 189)}{2} = 2997

The sum of the first 37 terms of the arithmetic sequence is 2997.

6 0
3 years ago
When four times a number n is decreased by 3 it’s at most 21
pashok25 [27]
The number is = 6
……………………………….
8 0
3 years ago
How many positive integers not exceeding 1000 are not divisible by either 4 or 6?
san4es73 [151]
\left\lfloor\dfrac{1000}4\right\rfloor=250

\left\lfloor\dfrac{1000}6\right\rfloor=166

\left\lfloor\dfrac{1000}{\mathrm{lcm}(4,6)}\right\rfloor=\left\lfloor\dfrac{1000}{12}\right\rfloor=83

250+166-83=333
7 0
3 years ago
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