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2 answers:
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Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>It is given by the derivative at x = x0, that is:
.
In this problem, the function is:
Hence the derivative is:
For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
More can be learned about derivatives and tangent lines at brainly.com/question/8174665
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Answer:
7
Step-by-step explanation:
Using the exact values for
cos45° = and tan60° =
, then
2(cos²45° + tan²60°)
= 2( ( )² + (
)² )
= 2( + 3 ) ← distribute
= 1 + 6
= 7