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4 years ago

How is shading a grid to show 1 tenth different from shading a grid to show 1 hundreth?

1 answer:

8 0

Shading a grid to show 1 tenth means that for every shaded square there are 9 unshaded squares. To show 1 hundreth, for every shaded square there should be 99 unshaded squares. Example: Suppose a grid has 100 squares total. For 1 tenth, you would shade 10 squares, leaving 90 squares unshaded - maintaining the ratio of one shaded square per nine unshaded square. On the same grid, 1 hundreth would require 1 shaded square with the remaining 99 squares unshaded.

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Inez is saving money to buy a dress for the homecoming dance. The dress costs $345. She has

Anna007 [38]

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Step-by-step explanation:

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4 years ago

Read 2 more answers

Please help!!!! Find X and Y

Rudik [331]

Answer: X=15 , Y=15 $\sqrt{3}$

Step-by-step explanation:

This triangle is a 30, 60, 90 so that means it would be - a, 2a, a $\sqrt{3}$ on each side, so add that all together and you get x-15 and y-15 $\sqrt{3}$

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4 years ago

A psychologist wants to see if a certain company has fair hiring practices in an industry where 60% of the workers are men and 4

makvit [3.9K]

Answer:

A) $H_{0}$ : p=0.5 (At least half of the workers are women,fair)

B) $H_{a}$ : p<0.5 (Less than half of the workers are women,unfair)

C) critical value of the test statistic is 1.64 (one tailed)

D) Test statistic is ≈ 0.29

E) Since 0.29<1.64, we fail to reject the null hypothesis. There is no significant evidence that the company has unfair hiring practices at 0.05 significance level.

Step-by-step explanation:

Let p be the proportion of women workers in the company. Null and alternative hypotheses are

$H_{0}$ : p=0.5 (At least half of the workers are women,fair)

$H_{a}$ : p<0.5 (Less than half of the workers are women,unfair)

Test statistic can be found using the equation:

z= $\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of women workers ( $\frac{55}{107} =0.514$ )

p is the proportion assumed under null hypothesis. (0.5)

N is the sample size (55+52=107)

Then z= $\frac{0.514-0.5}{\sqrt{\frac{0.5*0.5}{107} } }$ ≈ 0.29

For alpha 0.05, critical value of the test statistic is 1.64 (one tailed)

Since 0.29<1.64, we fail to reject the null hypothesis. There is no significant evidence that the company has unfair hiring practices at 0.05 significance level.

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3 years ago

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steposvetlana [31]

Answer: $11.45

Step-by-step explanation:

Food pill: $9

Tax: 6%

Tip: 20%

$x=(9)+(9)(0.06)+[(9)+(9)(0.06)](0.20)\\x=11.45$

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4 years ago

Please answer

Leno4ka [110]

Answer:

A. 3.

Step-by-step explanation:

As there are only three numbers above the number 3 on a die (4, 5, 6), there could only be three positive outcomes for the situation.

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3 years ago