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Lilit [14]
4 years ago
8

Jeremy is looking at two different options for a new gym membership. Plan A has a fee of $40 plus an additional fee of $19.95 pe

r month. With this plan, the first 3 months are free. Plan B has a fee of $59.85 plus an additional fee of $29.95 per month. With this plan, the first 6 months are free. After how many months would both options cost the same amount?
Mathematics
1 answer:
klio [65]4 years ago
8 0
Dang I just had this
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Ryan has a bank account balance of −$17.62. As soon as he realizes this, he deposits $26.50 in the account.
nirvana33 [79]

Answer:

$466.93

Step-by-step explanation:

I multiplied by 26.50 & 17.62 and that got me $466.93. Or you can divide that into 17.62 = $1.50

4 0
3 years ago
Hi ppl I rlly need help I’ve been off school and I rlly need to know the mean of 263 240 and 256 also I need to know the mean of
SSSSS [86.1K]

Answer:

So the mean of 263,240,256 is 253 and the mean of 12,13,17 is 14

Step-by-step explanation:

To get the mean of these numbers you add all three of them together then you divide them by the amount of numbers so you are going to add 263+240+256=759 then you divide by 3

759 \div 3 = 253

5 0
3 years ago
A book sold 3,400 copies in its first month of release. Suppose this represents 8.3 of the number of copies sold to date. How ma
Volgvan

Answer:

40963

Step-by-step explanation:

im assuming that its 8.3%

3400 ÷ 8.3 = 1% = 409.63....

1% x 100 = 100% of copies = 40963

7 0
4 years ago
A: {71,73,79,83,87} B:{57,59,61,67}
Jobisdone [24]

Answer:

\frac{3}{5}.

Step-by-step explanation:

We have been given two sets as A: {71,73,79,83,87} B:{57,59,61,67}. We are asked to find the probability that both numbers are prime, if one number is selected at random from set A, and one number is selected at random from set B.

We can see that in set A, there is only one non-prime number that is 87 as it is divisible by 3.

So there are 4 prime number in set A and total numbers are 5.

P(\text{Prime number from A})=\frac{4}{5}

We can see that in set B, there is only one non-prime number that is 57 as it is divisible by 3.

So there are 3 prime number in set B and total numbers are 4.

P(\text{Prime number from B})=\frac{3}{4}

Now, we will multiply both probabilities to find the probability that both numbers are prime. We are multiplying probabilities because both events are independent.

P(\text{Prime number from A and B})=\frac{4}{5}\times \frac{3}{4}

P(\text{Prime number from A and B})=\frac{1}{5}\times \frac{3}{1}

P(\text{Prime number from A and B})=\frac{3}{5}

Therefore, the probability that both numbers are prime would be \frac{3}{5}.

4 0
3 years ago
A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐
cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0
3 years ago
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