Which numbers are less than -8/3? Select all that apply.

Here is 13 & 16 .. take you time :)

Serhud [2]

Answer:

13) 1 Remove parentheses.

4

0.

×

4

−

3

4

0.

×4

−3

2 Use Negative Power Rule:

x

−

a

=

1

x

a

x

−a

=

x

a

1

.

4

0.

×

1

4

3

4

0.

×

4

3

1

3 Simplify

4

3

4

3

to

64

64.

4

0.

×

1

64

4

0.

×

64

1

4 Simplify.

4

0.

64

4

0

16) 6

0

6.

×2

6

2 Simplify

2

6

2

6

to

64

64.

0

6.

×

64

0

6.

×64

I hope this helps you

7 0

3 years ago

Read 2 more answers

Correct answers only please!

Zina [86]

Answer:

C. 56.2 is correct

Step-by-step explanation:

24.5x = 1378

x =56.24 mph

3 0

3 years ago

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Find the z-score boundaries that separate a normal distribution as described in each of the following. a. The middle 20% from th

Anna007 [38]

Answer:

a) The boundaries are $Z = \pm 0.253$

b) The boundaries are $Z = \pm 0.675$ .

c) The boundaries are $Z = \pm 1.96$ .

d) The boundaries are $Z = \pm 2.575$ .

Step-by-step explanation:

Z-score:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. The middle 20% from the 80% in the tails.

The middle 20% is between the 50 - (20/2) = 40th percentile and the 50 + (20/2) = 60th percentile:

40th percentile: Z has a pvalue of 0.4, so Z = -0.253.

60th percentile: Z has a pvalue of 0.6, so Z = 0.253.

The boundaries are $Z = \pm 0.253$ .

b. The middle 50% from the 50% in the tails.

The middle 50% is between the 50 - (50/2) = 25th percentile and the 50 + (50/2) = 75th percentile:

25th percentile: Z has a pvalue of 0.25, so Z = -0.675.

75th percentile: Z has a pvalue of 0.75, so Z = 0.675.

The boundaries are $Z = \pm 0.675$ .

c. The middle 95% from the 5% in the tails.

The middle 95% is between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile:

2.5th percentile: Z has a pvalue of 0.025, so Z = -1.96.

97.5th percentile: Z has a pvalue of 0.975, so Z = 1.96.

The boundaries are $Z = \pm 1.96$ .

d. The middle 99% from the 1% in the tails.

The middle 99% is between the 50 - (99/2) = 0.5th percentile and the 50 + (99/2) = 99.5th percentile:

0.5th percentile: Z has a pvalue of 0.005, so Z = -2.575.

99.5th percentile: Z has a pvalue of 0.995, so Z = 2.575.

The boundaries are $Z = \pm 2.575$ .

6 0

3 years ago

Delia, Edwin and Freya share some money in the ratio 5:7:8 Freya's share is £1600 how much did they share?

andrey2020 [161]

Answer: £ 400,560,640

Step-by-step explanation:

Given

Delia, Edwin, and Freya share £1600 in the ratio $5:7:8$

Suppose, their shares are 5x,7x, and 8x such that the ratio remains the same.

The sum of their shares must be £1600

$\Rightarrow 5x+7x+8x=1600\\\Rightarrow 20x=1600\\\\\Rightarrow x=\dfrac{1600}{20}\\\\\Rightarrow x=80$

Their share is

Delia: $5\times 80=400$

Edwin: $7\times 80=560$

Freya: $8\times 80=640$

7 0

3 years ago

Help and explain plzzz

user100 [1]

The answer is B. She sells each orange for $0.50 and the question is asking for the total amount of money she will make by selling a certain amount of oranges. t represents the total so the equation will to equal to t. c is the number of oranges she will sell so c multiplied by $0.50 will give the total amount of money she will make.

6 0

4 years ago

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