Part A:What percentage of the total students surveyed like both watching television and reading?
The total amount of student is 230
The amount of students that like to read and watch television is 80
As a fraction it is 80/230
Turn that to a percentage
It is:34.7826%
Part A=34.7826%
Part B:What is the probability that a student does not like watching television also does not like reading?
On the table it shows 20
So the probability is 20/230
Part B=20/230
6-4[x-1-(y+3)]+5y
6-4(x+1-y-3)+5y
6-4x-4+4y+12+5y
6-4+12-4x+4y+5y
14-4x+9y
Answer:
2. It will be a 7 3/4in x 12 1/4in rectangle
4. 31,987 in^2
6. 30 547/640 in^3
Step-by-step explanation:
2. This is a cross-section. In order to get the cross-section, you take your shape. (a 7 3/4 x 12 1/4 x 3 3/4 rectangle) and essentially you remove the last dimension (Height).
4. Take your surface area value (319 35/64) and multiply it by 100 (10 per dimension length and width). This leaves you with 319.87x100 = 31,987 in^2
6. (308 35/64)/10. Pretty easy, take 308.546875, divide by 10, and you get 30.8546875, which is 30 547/640 in^3 in fractions.
Answer:
120
Explanation:
If you do 4x+36+3x-3=180, you get 21. 21 is NOT the answer, it is x. x=21 so then you do 4 (21)+36 and you get 120. So 120 is the answer. Your Welcome