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ZanzabumX [31]
3 years ago
15

Describe different ways that you can Showa story problem. Use one of the problems in this lesson as your example

Mathematics
1 answer:
dedylja [7]3 years ago
4 0

Answer:

2. We have given the total of 21 children

And 7 children left the library that means 7 have reduced from total

So, the remaining children in the library would be 21-7 = 14

3. Suppose I have a pizza which has 16 slices and i have eaten 12 slices.How many slices have left?

Solution for 3. Total number of slices 16

And 12 have been eaten so, slices i will be left with is 16 -12=4 slices.

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F(x) = 3x^2 + 10x -25 g(x) = 9x^2 -25 Find (f/g)(x)
anzhelika [568]

the quotient will be x+3 and remainder is x^2+10x-100

MARK ME BRAINLIEST PLEASE

3 0
2 years ago
For what values of m does the graph of y = 3x2 + 7x + m have two x-intercepts
Irina18 [472]

we are given

y=3x^2+7x+m

To find x-intercept means we have to find zeros

and for finding zeros , we will use quadratic formula

and we have it has two x-intercepts

so, it's discriminant must be greater than 0

so, we will find discriminant

D=\sqrt{b^2-4ac}

now, we can compare with

y=ax^2+bx+c

y=3x^2+7x+m

and then we can find a , b and c

a=3,b=7,c=m

now, we can find D

D=\sqrt{7^2-4*3*m}

D=\sqrt{49-12m}

It has two x-intercepts

so,

D=\sqrt{49-12m}>0

now, we can solve for m

49-12m>0

12m

m............Answer

8 0
3 years ago
Read 2 more answers
RELATION OR FUNCTION?
sladkih [1.3K]

Answer:

FUNCTIONNNNN

Step-by-step explanation:

7 0
3 years ago
( 20points please ) -22+(-16)=
hjlf

-22+(-16)

-22-16= -38

5 0
4 years ago
Read 2 more answers
Y+2 = -3(x – 4)<br> Complete the missing value in the solution to the equation. <br><br> (?, -2)
ss7ja [257]

Answer:

The missing value in the solution to

the equation will be:

  • x=4

Step-by-step explanation:

Given the equation

y+2\:=-3\left(x\:-\:4\right)

As the value of y = -2 is given.

so substituting the value y = -2 in the equation to find the missing value

\left(-2\right)+2\:=-3\left(x\:-\:4\right)

switch the sides

-3\left(x-4\right)=\left(-2\right)+2

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

-3\left(x-4\right)=-2+2

-3\left(x-4\right)=0

\mathrm{Divide\:both\:sides\:by\:}-3

\frac{-3\left(x-4\right)}{-3}=\frac{0}{-3}

x-4=0

x=4

Therefore, the missing value in the solution to

the equation will be:

  • x=4
4 0
3 years ago
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