Answer:
a. Let us consider that L is responsible for late and l is responsible for early. From the mentioned data, it can be concluded that allele L or late is dominant over early. By crossing plants 1 and 4 we get the expected ratio of 3: 1, which shows that it follows Mendel's law of dominant.
b. The genotype of all the four plants are:
1st plant = Ll
2nd plant = ll
3rd plant = LL
4th plant = Ll
c. If the plant 1 is self-fertilized then the expected progeny will be 3 (late): 1 (early).
In case if the 2nd plant is self-fertilized, the expected progeny will be only early.
In case if the 3rd plant is self-fertilized, the expected progeny will be only late.
In case if the 4th plant is self-fertilized, the expected progeny will be 3 (late): 1 (early).
Answer:
The nucleus, cell membrane and cytoplasm.
Explanation:
The nucleus, cell membrane and cytoplasm are three elements that cannot be absent in a cell because they are necessary for the survival of the cell. The nucleus controls and regulates the activities happening inside the cell e.g. growth and metabolism etc. Cell membrane acts as a wall to protect the inner part of the cell from the external environment as well as allows nutrients and gases inside and outside the cell. Cytoplasm serves as a medium for the conduction of nutrients and waste from on place to another and also for the medium for organelles in which they floats.
Translation is the process by which a protein is synthesized from the information contained in a molecule of messenger RNA (mRNA). ... Translation occurs in a structure called the ribosome, which is a factory for the synthesis of proteins. -google
Abnormal cellular growth is caused by DNA mutations that divide in a much higher rate than normal
Answer:
a. the environmental variance (VE) = 3.5 g ²
b. 17.5 g ² for population
c. the heritability of broad sense (H2) = 0.83
Explanation:
a.With the information we have we can infer that environmental factors influence A, which is considered isogenic, thus, the environmental variance (VE) = 3.5 g ²
b.When studying population B, comparing it without environmental changes with respect to population A, we found that its total variance (VT) = 21.0g ²
We generate the following formula with the data obtained previously to find the genetic variation
VT = VE + VG
then VG = VT-VE
replacing data:
VG = 21.0 - 3.5 = 17.5 g ² for population
c. Regarding the heritability of broad sense (H2) in population B, we can reach the result with the data previously obtained like this:
H2 = VG / VT = 17.5 / 21.0 = 0.83
