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3 years ago

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beth and kristine ride their bikes to school in the morning. beth has to ride 1 7/32 miles. kristine has to ride 39/32 miles. wh

o rides the farthest to reach school ?

1 answer:

VikaD [51]3 years ago

5 0

They both ride the same amount of miles

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Use technology or a z-score table to answer the question.

Alik [6]

Answer:

The second choice: Approximately $65.2\%$ of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each $z$ entry has two decimal places.

Let $\mu$ represent the mean of a normal distribution of variable $X$ . Let $\sigma$ be the standard deviation of the distribution. The z-score for the observation $x$ would be:

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question,

$\mu = 240$ .
$\sigma = 9.3$ .

Calculate the z-score for $x_1 = 225$ and $x_2 = 245$ . Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

$\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}$ .

$\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}$ .

The question is asking for the probability $P(225 \le X \le 245)$ (where $X$ is between two values.) In this case, that's the same as $P(-1.61 \le Z \le 0.54)$ .

Keep in mind that the probabilities on many z-table correspond to probability of $P(Z \le z)$ (where $Z$ is no greater than one value.) Therefore, apply the identity $P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1)$ to rewrite $P(-1.61 \le Z \le 0.54)$ as the difference between two probabilities:

$P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61)$ .

Look up the z-table for $P(Z \le 0.54)$ and $P(Z \le -1.61)$ :

$P(Z \le 0.54)\approx 0.70540$ .
$P(Z \le -1.61) \approx 0.05370$ .

$\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}$ .

3 0

3 years ago

Mr. Omar assigns homework to his class and the homework requires students to

pychu [463]

Answer: no he is not correct
648
/ \
162 4
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81 2 2 2
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9 9
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3 3 3 3

7 0

3 years ago

Simplify the expression 6C2

iVinArrow [24]

Answer:

$^6C_2=15$

Step-by-step explanation:

Recall the formula:

$^nC_r=\frac{n!}{(n-r)!r!}$

We apply this formula to simplify $^6C_2$

This implies that:

$^6C_2=\frac{6!}{(6-2)!2!}$

$^6C_2=\frac{6!}{4!2!}$

$^6C_2=\frac{6\times5\times4!}{4!\times 2\times1}$

This simplifies to

$^6C_2=\frac{6\times5}{2\times1}$

$^6C_2=\frac{3\times5}{1\times1}=15$

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3 years ago

If 160,000÷n=4 then what is n?

shusha [124]

160,000/4 = n
n = 40,000

Answer: n = 40,000

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3 years ago

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Which undefined geometric term can be described as a one-dimensional set of points that has no beginning or end?

Grace [21]

It’s c (plane) if your asking for two-dimensional set of points

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3 years ago