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tensa zangetsu [6.8K]
3 years ago
11

To compare and order fractions,the fraction can be written with a​

Mathematics
1 answer:
Greeley [361]3 years ago
5 0
Common denominator i believe. i’m not sure. hope this helps
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Aiden borrows a book from a public library. He read a few pages on day one. On day two, he reads twice the number of pages than
Fofino [41]

Let the number of pages read on day 1 be = x

Then on day 2 he read twice the pages from day one, it is = 2x

On 3rd day he read 6 pages less than 1st day, it is = x-6

Total pages are = 458

The equation becomes: x+2x+x-6=458

4x-6=458

4x=464

x=116

So on the third day, Aiden read x-6=116-6=110 pages.

5 0
3 years ago
1 ≤ n, k ≤ 10 ^ 5 1 ≤ x ≤ 10 ^ 5<br> Alguém me ajuda?
enot [183]

Answer:

ask your teacher for help

Step-by-step explanation:

8 0
2 years ago
What is 10 blankets plus 56 more blankets X2
Debora [2.8K]
The answer to this question should be 114
6 0
3 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
A population of size 320 has a proportion equal to .60 for the characteristic of interest. What are the mean and the standard de
tiny-mole [99]

Answer:

The answer is c.) 0.6 and 0.14

Step-by-step explanation:

Given population has a size of 320.

The proportion of population = 0.6

The mean of population, p = 0.6

The mean of sample, \hat{p}= 0.6

Therefore \hat{q}  = 1 - \hat{p} = 1 - 0.6  = 0.4

The sample size  = 12

Therefore the standard deviation of the sample,

s = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n} }  = \sqrt{\frac{0.6 \times 0.4}{12} }  = 0.1414

The mean and the standard deviation for a sample size of 12 are 0.6 and 0.14 respectively.

The answer is c.) 0.6 and 0.14

6 0
3 years ago
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