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kap26 [50]
2 years ago
12

Which of the following is the final fate for average sized stars?

Computers and Technology
1 answer:
schepotkina [342]2 years ago
7 0
Black holes correct.......
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Keion works as a freelancer creating websites and designing logos for clients. He recently had a hard drive failure and lost wor
coldgirl [10]

Answer:

RAID 1

Explanation:

RAID is a data storage virtualization technology that combines multiple physical disk drive components into one or more logical units for the purposes of data redundancy, performance improvement, or both. RAID 1 requires a minimum of two physical drives, as data is written simultaneously to two places. The drives are essentially mirror images of each other, so if one drive fails, the other one can take over and provide access to the data that's stored on that drive.

3 0
3 years ago
The memory capacity in bits for performing the operation y = f (x) using the table lookup method, where x is an 8-bit number and
Flura [38]

Answer:

The page field is 8-bit wide, then the page size is 256 bytes.

Using the subdivision above, the first level page table points to 1024 2nd  level page tables, each pointing to 256 3rd page tables, each containing 64 pages. The program's address space consists of 1024 pages, thus we need we need 16 third-level page tables. Therefore we need 16 entries in a 2nd level page table, and one entry in the first level page table. Therefore the size is: 1024 entries for the first table, 256 entries for the 2nd level page table, and 16 3rd level page table containing 64 entries each. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 2 (one second-level paget table) + 16 * 64 * 2 (16 third-level page tables) = 4608 bytes.

First, the stack, data and code segments are at addresses that require having 3 page tables entries active in the first level page table. For 64K, you need 256 pages, or 4 third-level page tables. For 600K, you need 2400 pages, or 38 third-level page tables and for 48K you need 192 pages or 3 third-level page tables. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 3 * 2 (3 second-level page tables) + 64 * (38+4+3)* 2 (38 third-level page tables for data segment, 4 for stack and 3 for code segment) = 9344 bytes.

Explanation:

16 E the answer

5 0
2 years ago
What is meant by byte in computer terminology​
dsp73

Answer:

Byte, the basic unit of information in computer storage and processing. A byte consists of 8 adjacent binary digits (bits), each of which consists of a 0 or 1. The string of bits making up a byte is processed as a unit by a computer; bytes are the smallest operable units of storage in computer technology.

Explanation:

Can I be brainliest? TYSMMMMMM      

7 0
3 years ago
Read 2 more answers
A musician has recorded some initial ideas for new songs which she wishes to share with her bandmates. As these are initial idea
Ugo [173]

Answer:

1.save the audio using a low sampling rate

2.save the audio using a low bit depth

Explanation:

1. if the quality of the audio is low then the size of the audio will also be low and which will make the size of the data to be less and also easier to download

3 0
3 years ago
The count function is used to total the values stored in numeric columns.
Dovator [93]

Answer : False.

The function to total the values stored in numeric columns is the SUM function.

5 0
3 years ago
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