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butalik [34]
3 years ago
7

Assuming that we only support BEQ and ADD instructions, discuss how changes in the given latency of this resource affect the cyc

le time of the processor. Assume that the latencies of other resources do not change?
Computers and Technology
1 answer:
sertanlavr [38]3 years ago
6 0

Answer:

Refer below.

Explanation:

Because we are inserting commands to beq, we will need an execution of the ALU, and then a register write. This result in and increase cycle time of the PC relative branch:

440+90=530ps.

As it is the longest time to execute, so its a critical path

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Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type
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Solution :

#include  $$

#include $$

#include $$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal$\text{To}$Binary(char* hexdec)

{

 

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$(sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

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case 'F':

case 'f':

strcat(string, "1111");

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default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

 

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

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Usually they hold 15-20 as the minimum of the portfolios

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Answer:

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Some products specify the penalties which are given to a person who makes unauthorized copies of their product and this is done to clearly educate to avoid ignorance claims.

A good product should have clear lettering which are legible and can be easily read, and should also have reasonable copyright protection.

<h3>What is Copyright?</h3>

This refers to the licensing which is done for a product and is also legally backed which prevents a person from illegally using or redistributing the work of a creator without their explicit consent.

Read more about copyright infringement here:
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