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eimsori [14]
3 years ago
5

5/6w+21=-1/3(2w-9).

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
7 0
I believe this question logically tells us to find the value of w. The two equations are already equated. Since there is 1 unknown and 1 equation, the system is solvable. The solution is as follows:

5/(6w+21) = -1/3(2w - 9)
5/(6w+21) = -1/(6w - 27)
Cross multiplying the terms:
5(6w - 27) = -1(6w +21)
30w - 135 = -6w - 21
30w + 6w = -21 + 135 = 114
36w = 114
w = 114/36
w = 19/6 or 3.167
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5 0
3 years ago
Write an equation for a circle with a diameter that has endpoints at (–10, 1) and (–8, 5). Round to the nearest tenth if necessa
satela [25.4K]

The standard form for the equation of a circle is :

<span><span><span> (x−h)^</span>2</span>+<span><span>(y−k)^</span>2</span>=<span>r2</span></span><span> ----------- EQ(1)
</span><span> where </span><span>handk</span><span> are the </span><span>x and y</span><span> coordinates of the center of the circle and </span>r<span> is the radius.
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3 years ago
Tipos de ecuaciones ​
Yanka [14]

Answer:

Ecuaciones algebraicas. De primer grado o lineales. De segundo grado o cuadráticas...

Ecuaciones trascendentes, cuando involucran funciones no polinómicas, como las funciones trigonométricas, exponenciales, logarítmicas, etc.

Ecuaciones diferenciales. Ordinarias...

Ecuaciones integrales.

Ecuaciones funcionales.

Hope this helps! :)

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faltersainse [42]

Answer:

one balloon will be left over

Step-by-step explanation:

6 0
3 years ago
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