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Valentin [98]
3 years ago
6

Given the statement "If a line is horizontal, then it has slope equal to zero,” what is its contrapositive? If a line is horizon

tal, then it has zero slope. If a line has zero slope, then it is a horizontal line. If a line is not horizontal, then it does not have zero slope. If a line does not have zero slope, then it is not a horizontal line.
Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0

Answer:

the last option is correct

Step-by-step explanation:

If a line does not have zero slope, then it is not a horizontal line.

givi [52]3 years ago
7 0

Contrapositive are the statements in which we switch the hypothesis and the conclusion of the statement and then we take the negation of both.

Here the hypothesis is " A line is horizontal"

And the conclusion is " slope equal to zero"

In order to make the contrapositive statement we switch the hypothesis and conclusion and then take negation.

Therefore, the contrapositive statement is given by

If a line does not have zero slope, then it is not a horizontal line.

Last option is correct.

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Answer: 120, 60, 180

Step-by-step explanation:

1) Area of a rectangle's formula is:

l × w

So, looking at the diagram, we get:

6 × 20 = 120 cm²

2) Area of a trapezoid's formula is:

\frac{a+b}{2} × h (where both a and b are the different base lengths)

So, looking at the diagram, we get:

\frac{10+20}{2} × 4 = 60 cm²

3) Add both to find the area of the entire figure.

120 + 60 = 180 cm²

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Convert the given measurement of water to the unit indicated 5.8kg to cm cubed
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Given sin(−θ)=−1/6 and tanθ=−√35/35 What is the value of cosθ?
murzikaleks [220]

Answer:

cos(\theta)=-\frac{\sqrt{35} }{6}

Step-by-step explanation:

Recall the negative angle identity for the sine function:

sin(- \theta)=-sin(\theta)  

Then, we can find the value of  sin(\theta):

sin(\theta)=-sin(-\theta)\\sin(\theta) =-(-\frac{1}{6} )\\sin(\theta)= \frac{1}{6}

Now recall the definition of the tangent function:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Therefore, now that we know the value of sin(\theta), we can solve in this equation for cos(\theta)

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-\frac{\sqrt{35} }{35} =\frac{1/6}{cos(\theta)} \\cos(\theta)=-\frac{\frac{1}{6} }{\frac{\sqrt{35} }{35} } \\cos(\theta)=-\frac{35}{6\,\sqrt{35} } \\cos(\theta)=-\frac{\sqrt{35} }{6}

5 0
3 years ago
What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5
swat32

Let k:y=m_1x+b_1 and l:y=m_2x+b_2

l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}

We have y=-\dfrac{2}{3}x+5\to _1=-\dfrac{2}{3}

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Put the coordinates of the point (8, 1) to the equation of a line:

1=\dfrac{3}{2}(8)+b

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1=12+b       <em>subtract 11 from both sides</em>

-11=b\to b=-11

Answer: \boxed{y=\dfrac{3}{2}x-11}

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5 blocks away from W to K.
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