Given h(t)=-2(t+5)^2+4, find h(-8)
-334
-14
-45
-445
1 answer:
Substitute -8 for t in the expression, and now you have: h(-8) = -2[(-8) + 5]^2 + 4. Solve inside the parentheses; add -8 and 5.
h(-8) = -2[-3]^2 + 4, solve exponents next by squaring -3.
h(-8) = -2[9] + 4, multiply -2 and 9.
h(-8) = [-18] + 4, add -18 and 4.
h(-8) = -14.
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m =(y2-y1)/(x2-x1)
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m = -1/5
slope of the line that is perpendicular = 5
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<span>31over 5 x 5 over 8 = 31/8
answer </span>3/1= 3.87500
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