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Gennadij [26K]
3 years ago
9

Given h(t)=-2(t+5)^2+4, find h(-8) -334 -14 -45 -445

Mathematics
1 answer:
stepladder [879]3 years ago
6 0

Substitute -8 for t in the expression, and now you have: h(-8) = -2[(-8) + 5]^2 + 4. Solve inside the parentheses; add -8 and 5.

h(-8) = -2[-3]^2 + 4, solve exponents next by squaring -3.

h(-8) = -2[9] + 4, multiply -2 and 9.

h(-8) = [-18] + 4, add -18 and 4.

h(-8) = -14.

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Sarah has a collection of nickels, dimes, and quarters worth $28.75. She has 10 more dimes than nickels and twice as many quarte
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Answer:

Step-by-step explanation:

Write an equation for each statement:

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"Sarah has a collection of nickels, dimes, and quarters worth $15.75."

.05n + .1d + .25q = 15.75

:

"She has 10 more dimes than nickels"

d = n + 10

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"twice as many quarters as dimes."

q = 2d

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How many coins of each kind does she have?

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Take the 2nd equation and arrange it so n is in terms of d also

n + 10 = d

n = (d - 10)

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In the 1st equation substitute (d-10) for n and 2d for q:

.05n + .1d + .25q = 15.75

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.05(d-10) + .1d + .25(2d) = 15.75

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.05d - .5 + .1d + .5d = 15.75

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.65d - .5 = 15.75

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.65d = 15.75 + .5

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.65d = 16.25

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d = 16.25/.65

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d = 25 dimes

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Remember the statement "twice as many quarters as dimes."

q = 2(25)

q = 50 quarters

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The statement "She has 10 more dimes than nickels"

n = 25 - 10

n - 15 nickels

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Check our solutions

.05(15) + .1(25) + .25(50) =

.75 + 2.50 + 12.50 = 15.75 proves our solutions

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