Question

Given h(t)=-2(t+5)^2+4, find h(-8) -334 -14 -45 -445

Answer 1

Substitute -8 for t in the expression, and now you have: h(-8) = -2[(-8) + 5]^2 + 4. Solve inside the parentheses; add -8 and 5.

h(-8) = -2[-3]^2 + 4, solve exponents next by squaring -3.

h(-8) = -2[9] + 4, multiply -2 and 9.

h(-8) = [-18] + 4, add -18 and 4.

h(-8) = -14.