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Deffense [45]
4 years ago
7

NEED ANSWERS QUICK PLEASE

Mathematics
1 answer:
Contact [7]4 years ago
5 0
No solution:
3/2x + 2.3 - 1/2x = 4.3 + x
5r + 2 = 6r + 3 - r

one solution:
2x + 2/3 = 2x + 4/5 - 4x
3.2p - 2.5 + 2.1p = 5p - 7/2

infinitely many:
17/4 + 4.2y - 9/4 = 2.2y + 6 + 2y - 4
-2z + 2 + 4z = 16/5 + 2x - 6/5
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What does venerable mean​
Helga [31]

Answer:

accorded a great deal of respect, especially because of age, wisdom, or character.

"a venerable statesman"

Similar:

respected

venerated

revered

reverenced

Step-by-step explanation:

Hope it helps u , Good luck ^.^

5 0
3 years ago
PLEASE HELP .........
joja [24]

Answer:

11860.22 rev/hour

Step-by-step explanation:

The diameter if a cylinder, d = 21.02 inches

Radius, r = 10.51  inches

or

r = 0.875 feet

The linear speed of a point on the cylinder's surface is 18.12 ft/sec.

We need to find the angular speed of the cylinder.

The relation between the linear speed and the angular speed is given by :

v=r\omega

Where

\omega is angular speed

\omega=\dfrac{v}{r}\\\\\omega=\dfrac{18.12}{0.875}\\\\\omega=20.7\ rad/s

or

\omega=11860.22\ rev/hour

So, the required angular speed of the cylinder is 11860.22 rev/hour.

4 0
3 years ago
Which gives the line of best fit?
BartSMP [9]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
Answer #2 please ASAP
Len [333]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 1.6

Explanation:

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

6 0
3 years ago
The probability that a data communications system will have high selectivity is 0.72, and the probability that it will have high
34kurt

Let us assume that even F represents fidelity and event S represents selectivity.

We have been given the probabilities:

P(S) = 0.72, P(F) = 0.59 and P(S\cap F)=0.33

We need to find the conditional probability that a system with high fidelity will also have high selectivity. We know the conditional probability formula:

P(\frac{S}{F})=\frac{P(S\cup F)}{P(F)}

Upon substituting the given values, we get:

P(\frac{S}{F})=\frac{0.33}{0.59}

P(\frac{S}{F})=\frac{33}{59}=0.56

4 0
3 years ago
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