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labwork [276]
4 years ago
14

Jacob wants to use an elevator to carry identical packages having the same weight. Each package weighs 3 pounds and Jacob weighs

99 pounds. If the elevator can carry a maximum of 300 pounds at a time, which inequality shows the maximum number of packages, n, that Jacob can carry with himself in the elevator if he is the only passenger?
Mathematics
1 answer:
zzz [600]4 years ago
7 0

Answer:

The required inequality that shows the maximum number of packages is n\leq 67.

Step-by-step explanation:

Consider the provided information.

Each package weighs 3 pounds and Jacob weighs 99 pounds.

let <em>n</em> is the maximum number of package that Jacob can carry with himself in the elevator.

Thus, the total weight of Jacob while having <em>n</em> packages on the elevator is:

3n+99

The elevator can carry a maximum of 300 pounds at a time, therefore.

3n+99\leq 300

Now, subtract 99 from both sides and divide the obtained inequality with 3.

3n+99-99\leq 300-99

3n\leq 201

\frac{3n}{3}\leq \frac{201}{3}

n\leq 67

Thus, the Jacob can carry maximum 67 packages.

Hence, the required inequality that shows the maximum number of packages is n\leq 67.

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