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Answer:
∠ ADC = 110°
Step-by-step explanation:
∠ CDE = 90° ( angle between perpendicular lines ) , then
∠ CDB + ∠ BDE = 90°
∠ CDB + 20° = 90° ( subtract 20° from both sides )
∠ CDB = 70°
∠ ADC and ∠ CDB are adjacent angles on a straight line and sum to 180° , so
∠ ADC + ∠ CDB = 180° , that is
∠ ADC + 70° = 180° ( subtract 70° from both sides )
∠ ADC = 110°
7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
Answer: x=49
Step by step explanation: to find one of the sides just subtract 35 from 60, then you get 35/25=x/35, which is 25x=1225, the last step is to divide both sides by 25 and you get the final result of 49
