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Orlov [11]
3 years ago
11

Which Graph correctly represents x+2y≤4?

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0

Answer with Step-by-step explanation:

We are given an inequality:

x+2y≤4

We have to determine its correct graph

  • In graph A and graph C (0,4) lies in shaded region but (0,4) does not satisfy the inequality

(since, 0+2×4=8 which is not less than or equal to 4)

Hence, A and C are not the graph of this inequality

  • In graph D (0,2) does not lie in shaded area but it satisfies the inequality

Hence, D is also not the graph of this inequality

Hence, correct graph of x+2y≤4 is:

Graph B

ryzh [129]3 years ago
4 0
It's graph B, remember you can use desmos
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Y=x+3
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3 years ago
On March 17th, Pinny Sporting Goods accepted a credit card purchase for $900. The credit card company charges a 2% service fee.
Vera_Pavlovna [14]

Answer:

A : debit to Service Charge Expense of $18.

Step-by-step explanation:

First, one should calculate the value, in dollars of the credit card service fee

Fee = 2% x $900 = $18.

Since this fee is classified as "money coming out" of the account, the entry to a record of this transaction should include a debit to Service Charge Expense of $18.

The correct answer is alternative A.

*The whole purchase amount ($900) should be credited and the service expense should be debited, unlike alternative C, which merges both entries into one.

6 0
3 years ago
Please someone give me an actual answer.​
barxatty [35]

Answer:

option 2

Step-by-step explanation:

3 0
3 years ago
The area of sector A08 is 48x and m<AOB = 270º. Find the radius of circle O.
Softa [21]

Answer:

Step-by-step explanation:

The first one gives us everything we need except the radius, which is easy enough to solve for if you're careful with your algebra. The area of a sector of a circle is given as:

A_s=\frac{\theta}{360}*\pi r^2 where θ is the measure of the central angle of the circle. For us, that fills in as follows:

48\pi=\frac{270}{360}*\pi r^2 and manipulate it as follows:

r^2=\frac{(360)(48\pi)}{270\pi} the π's cancel out, leaving us with simple multiplication and division to get

r = 8. Now for the next one, which is a bit more involved.

In order to find the area of the shaded part, we need to find the area of the right triangle there and subtract it from the area of the sector of the circle. First the area of the sector, which is given as:

A_s=\frac{\theta}{360}*\pi r^2 where θ again is the measure of the central angle of the circle, 90°:

A_s=\frac{90}{360}(3.1415)(10)^2 which simplifies a bit to

A_s=\frac{1}{4}(3.1415)(100), giving us an area of

A_s=78.5375m^2. Now onto the area of the triangle.

Since this triangle is inscribed in the circle and the circle's radius is 10, tha also gives us both the height and the base measures of the triangle. The area then is:

A_t=\frac{1}{2}(10)(10) which is

A_t=50m^2

Subtract that from the area of the sector to get that the shaded area is 28.5 square meters, choice A.

4 0
3 years ago
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