Let's make p stand for popcorn and d for drinks. Using those variables, we can create our equations:
2p + 3d = 18.25
4p + 2d = 27.50
From this, we can use substitution or elimination to solve:
For substitution, in the second equations, we could factor out a 2, divide both sides by 2, and then move the left over 2p to the other side to isolate d to put into the first equation.
For elimination, we can multiply the first equation by -2 so that we can remove the 4p and focus on solving for d.
I'll be using elimination in this case:
-2(2p + 3d = 18.25) --> -4p - 6d = -36.50
-4p - 6d = -36.50
4p + 2d = 27.50
-4d = -9.00
d = 2.25
4p + 2 * 2.25 = 27.50
4p + 4.50 = 27.50
4p = 23.00
p = 5.75
Now let's check our answer:
2 * 5.75 + 3 * 2.25 = 18.25
11.50 + 6.75 = 18.25
18.25 = 18.25
So drinks cost $2.25 and popcorn $5.75
P is just a definition: it's the ratio between a circle's diameter and its circumference. In other words, any circle circumference is approximately 3.14 (p) times longer (around) than its diameter length. Some old Greek dude discovered it a few thousand years ago... Let's do the first 3 problems together - by then I think you'll have confidence you can do the remaining 3! 1. If C = 2pr, then we substitute C = 2*3.14*6, = 37.68 2. If C = 2pr, then let's rearrange that so we can find r: divide both sides (to keep it equal) by 2p to get r by itself: C/2p = 2pr/2p, so r = C/2p. Now substitute: r = 24p/2p = 12 3. If C = 2pr, then r = C/2p (see #2 above), then r = d/2. If A = pr2, then A = p (C/2p)2. Substitute: A = p (32p/2p)2, or A = p (16)2 A = 3.14 * 256 = 803.84 Now can you complete #3 - #6? I bet you can... :-)
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♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>
➷ Multiply the total value by 1/4:
1/4 x 8 = 2
He practiced it for 2 hours.
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➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
You can use math-way or photo-math (app) for these kinds of questions!
<span>the temperature of a room, in degrees Fahrenheit, over time, t, in minutes increases in two time intervals.that are :
</span>
A. from t = 0 to t = 20 <span>
D. from t = 50 to t = 70
</span>See the attachment for graph.
