Answer:
the answer is let a b* ban me
Step-by-step explanation:
Use the fact that integrals are additive on their intervals. Mathematically, if , then
So we have
Answer:
1. x=6
2. x=2
Step-by-step explanation:
2:6
x:18
From 6 to 18, 6 was multiplied by 3. To keep the equality, we must multiply the other side by three as well. Therefore, x is equal to 2*3 which equals 6.
x=6.
5:7
(x+3):7
For this one, the second value did not change, so we know that x+3 has to equal 5. Therefore, x=2.
x=2
A and C- the maximum is the highest point on the curve and the minimum is the lowest, so A and C are correct
Answer:
Step-by-step explanation:
Explanation:
Start by writing out your starting expression
x
2
−
5
x
2
+
5
x
−
14
−
x
+
3
x
+
7
Next, factor the denominator of the first fraction
x
2
+
5
x
−
14
x
2
+
7
x
−
2
x
−
14
x
(
x
−
2
)
+
7
(
x
−
2
)
(
x
−
2
)
(
x
+
7
)
Your expression is thus equivalent to
x
2
−
5
(
x
−
2
)
⋅
(
x
+
7
)
−
x
+
3
x
+
7
Since you have to subtract two fractions, you need to find the commonon denominator first. To do that, multiply the second fraction by
x
−
2
x
−
2
x
2
−
5
(
x
−
2
)
⋅
(
x
+
7
)
−
(
x
+
3
)
⋅
(
x
−
2
)
(
x
−
2
)
⋅
(
x
+
7
)
This will get you
x
2
−
5
−
(
x
+
3
)
(
x
−
2
)
(
x
−
2
)
(
x
+
7
)
x
2
−
5
−
x
2
−
x
+
6
(
x
−
2
)
(
x
+
7
)
=
1
−
x
(
x
−
2
)
(
x
+
7
)