3 years ago

HELP!!!!! What is the exclusion of 57x^5/19x^2??

Mathematics

1 answer:

Setler [38]3 years ago

3 0

<span>57x^5/19x^2
= 3x^3

hope it helps</span>

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BRAINLIEST, THANK AND 5 STARS FOR RIGHT ANSWER!!!!

Strike441 [17]

Answer:

Step-by-step explanation:

$$ You did not state whether this is simple or compound interest.$ \\ \\ $Simple$ \\ \\ A=Prt\\ \\ t= \frac{A}{Pr}\\ \\ t= \frac{10100}{4400(.07)}\approx 33 \\ \\ $ Compound $ \\ \\ A=P(1+r)^t\\ \\ t=ln\frac{A}{P}/ln(1+r)\\ \\ t=ln\frac{10100}{4400}/ln(1.07)\\ \\ t\approx 12$

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3 years ago

The shape has which of the following coordinates

Rasek [7]

Step-by-step explanation:

1a. ( 3, -4)

1b. ( 8, -2)

1c. ( 10, -10)

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3 years ago

Which system of inequalities does the graph represent? Which test point satisfies both of the inequalities in that system?

aev [14]

Answer:

Ok so its -3;3

Step-by-step explanation:

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3 years ago

Read 2 more answers

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

zaharov [31]

After 6 years the investment is $5555.88

Step-by-step explanation:

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

The formula used to find future value is:

$A(t)=P(1+\frac{r}{n})^{nt}$

where A(t) = Accumulated amount

P = Principal Amount

r = annual rate

t= time

n= compounding periods per year

We are given:

P = $3600

r = 7.5 %

t = 6

n = 1

Putting values in formula:

$A(t)=P(1+\frac{r}{n})^{nt}\\A(t)=3600(1+\frac{0.075}{1})^{6*1}\\A(t)=3600(\frac{1.075}{1})^6\\A(t)=3600(1.075)^6\\A(t)=3600(1.543)\\A(t)=5555.88$

So, After 6 years the investment is $5555.88

Keywords: Compound Interest formula

Learn more about Compound Interest formula at:

#learnwithBrainly

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3 years ago

Help! Question is attached.

irakobra [83]

Look at the coefficient of x (the slope).

Is -2 positive or negative?

Since -2 is negative, The slope is negative.

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3 years ago