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abruzzese [7]
3 years ago
11

HELP>>>>>>>>PLZ I WILL KEEP UPPING POINT BCUZ I HAVE ALOT OF Q"S

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
7 0

Answer: the second one

Step-by-step explanation:

Because this equals x > -5

So the circle would be open with the arrow pointing to the right starting at -5

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Which is the initial value that shrinks an exponential growth function by 50%?
ValentinkaMS [17]
Suppose that the exponential growth function is  y = 4^x.

If x = 1, then y = 4^1 = 4.
If x = 3, then y = 4^3 = 64.

Let the initial value be 1/2.

The growth function is now y = 1/2 * 4^x.

If x =1, then y = 2 which is half of the y value before adding the 1/2.

If x = 3, then y = 1/2 * 64 = 32.

Answer: 1/2
7 0
3 years ago
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Jessie has baked 30 out of 120 cookies. what percent of the cookies did jessie not bake
astra-53 [7]
This is a percent problem which means 
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3 years ago
Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit.
kodGreya [7K]
The technology I used in helping me solve the problem is using Microsoft Excel. I made one column for the x values which were gathered from the choices, one column for f(x) whose equation is 8^(x-9), and another column for g(x) whose equation is log(3x) + 2. 

Inputing these equation to the last two columns yield the values shown in the picture.The 'NUM' means that the equation at that value of x is undefined. From the values, the correct solution would be 

(0,0), (9.2,1.5) and (9.6,3.5) to the f(x) equation
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5 0
3 years ago
If the hypotenuse of a right triangle is 2 sqrt 3 units long and one legs is sqrt 3 units long, how long is the other leg?
allochka39001 [22]
Theorem of Pythagoras: a²+b²=c², where a, b is legs and c is hypotenuse.

We've got one leg known, let it be a=sqrt 3,
and the hypotenuse - c=2sqrt3


Putting these into the theorem, we get an equation: (sqrt3)²+b²=(2sqrt3)² . Solving it, we get:

3+b²=4*3
3+b²=12
b²=9

This equation has two possible roots: b=3 and b=-3. Since this is a triangle, there can't be a side with a negative value => b=3.

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4 0
3 years ago
Let theta be an angle in quadrant 2 such that cos theta =-3/4. Find the exact values of csc theta and cot theta.
Anna35 [415]

Step-by-step explanation:

Since cos(\theta) = -\frac{3}{4} we can get some information from this. First of all cos(\theta) is defined as \frac{adjacent}{hypotenuse}. So the adjacent side is 3 and the hypotenuse is 4. Using this we can find the opposite side to find sin(\theta) to calculate csc and cot of theta. So using the Pythagorean Theorem we can solve for the missing side. Also I forget to mention we have to calculate the sign of the adjacent side and the hypotenuse. Since you're given that the angle is in quadrant 2, that means the x-value is going to be negative, and the y-value is going to be negative. And the x really represents the adjacent side and the y represents the opposite. So the adjacent side is what's negative. and the opposite is positive

Pythagorean Theorem:

a^2+b^2=c^2

(-3)^2 + b^2 = 4^2

9 + b^2 = 16

b^2 = 7

b = \sqrt{7}

So now we can calculate sin(\theta).

sin(\theta) = \frac{\sqrt{7}}{4}

Now to calculate the exact value of csc you simply take the inverse. This gives you csc(\theta)=\frac{4}{\sqrt{7}}. Multiplying both sides by sqrt(7) to rational the denominator gives you \frac{4\sqrt7}{7}.

Now to calculate cot(theta) you  find the inverse of tan. Tan is defined as tan(\theta) = \frac{sin(\theta)}{cos(\theta)}. So all you do is take the inverse which is cot(\theta) = \frac{cos(\theta)}{sin(\theta)}.

Plug values in

cot(\theta) = \frac{-\frac{3}{4}}{\frac{4\sqrt{7}}{7}}

Keep, change, flip

-\frac{3}{4} * \frac{7}{4\sqrt7}

Multiply:

-\frac{21}{16\sqrt7}

Multiply both sides by sqrt(7)

-\frac{21\sqrt7}{112}

This is the value of cot(theta)

8 0
2 years ago
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