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masha68 [24]
3 years ago
10

(a/5) - (b/3) = (a/2) - (b/6), solve for a

Mathematics
1 answer:
Gnom [1K]3 years ago
5 0

Answer:

a =  -  \frac{10}{17} b

Step-by-step explanation:

(a/5) - (b/3) = (a/2) - (b/6)

+(B/3) + (b/3)

NOTE: use property of equality to isolate <em>b</em> from <em>a</em>

(a/5) = (b/3) + (a/2) - (b/6)

-(a/2) - (a/2)

NOTE: continue to use property of equality to isolate <em>a</em><em> </em>from <em>b</em>

(a/5) - (a/2) = (b/3) - (b/6)

60((a/5) - (a/2)) = ((b/3) - (b/6))60

NOTE: 60 is a common multiple of 5, 2, 3, and 6

12a - 30a = 20b - 10b

NOTE: combine alike terms

-17a = 10b

-17a/-17 = 10b/-17

NOTE: decide by -16 to find what a is equal to

a =  -  \frac{10}{17} b

Final answer

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In this subtraction, PR5T and 47Y6 represent 4-digit numbers. What number does PR5T represent?
Svetach [21]

Answer:

PR5T represents <em>6754.</em>

P = 6

R = 7

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Step-by-step explanation:

Let us try to understand the subtraction starting from the unit's digit.

   P R 5 T

-  4 7 Y 6

-----------------

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To get 8, 6 should be subtracted from 14

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So, T should be equal unit digit of 14 <em>i.e.</em> T = 4 and 1 should be carried over from the ten's digit of PR5T.

Now, let us move to ten's digit:

   P R 5 4

-  4 7 Y 6

-----------------

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To get 9, 6 should be subtracted from 15. But 1 is already carried to unit's place So, we have actually 14 here

14 - Y = 9

So, Y = 5

Moving to hundred's place:

R - carry - 7 = 9

Carry is 1, so R = unit's place of 9 + 8 i.e. R = 7

Moving to thousand's place:

P - carry - 4 = 1

Here carry is 1

So, P = 1 + 4 + 1 = 6

So, the number PR5T is <em>6754.</em>

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3 years ago
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