The dual-layer-IP allows ipv4 and ipv6 at the network layer to access a single tcp/udp stack.
<h3>What is the dual IP layer?</h3>
The word dual-stack is a word that connote a full or total duplication of all stages in the protocol stack ranging from its applications to the network layer.
Note that the dual-layer-IP method often gives room for a computer to run IPv4 and IPv6 simultaneously at the network layer, and all of the IP stack can access a different TCP/UDP stack.
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Answer:
<u>"Jargon"</u>
Explanation:
Great question, it is always good to ask away and get rid of any doubts that you may be having.
<em>Specialized vocabulary</em> is sometimes also known as <u>"Jargon"</u> . These are sets of words that are used specifically and uniquely for specific sets of groups or organizations.
For example Lawyers Judges and other law enforcement officials have their own Specialized vocabulary that are better understood by other people in Law enforcement, people that are not part of Law Enforcement might have a hard time understanding.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
Check the explanation
Explanation:
#!usr/bin/python
#FileName: sieve_once_again.py
#Python Version: 2.6.2
#Author: Rahul Raj
#Sat May 15 11:41:21 2010 IST
fi=0 #flag index for scaling with big numbers..
n=input('Prime Number(>2) Upto:')
s=range(3,n,2)
def next_non_zero():
"To find the first non zero element of the list s"
global fi,s
while True:
if s[fi]:return s[fi]
fi+=1
def sieve():
primelist=[2]
limit=(s[-1]-3)/2
largest=s[-1]
while True:
m=next_non_zero()
fi=s.index(m)
if m**2>largest:
primelist+=[prime for prime in s if prime] #appending rest of the non zero numbers
break
ind=(m*(m-1)/2)+s.index(m)
primelist.append(m)
while ind<=limit:
s[ind]=0
ind+=m
s[s.index(m)]=0
#print primelist
print 'Number of Primes upto %d: %d'%(n,len(primelist))
if __name__=='__main__':
sieve()
Answer:
def SwapMinMax ( myList ):
myList.sort()
myList[0], myList[len(myList)-1] = myList[len(myList)-1], myList[0]
return myList
Explanation:
By sorting the list, you ensure the smallest element will be in the initial position in the list and the largest element will be in the final position of the list.
Using the len method on the list, we can get the length of the list, and we need to subtract 1 to get the maximum element index of the list. Then we simply swap index 0 and the maximum index of the list.
Finally, we return the new sorted list that has swapped the positions of the lowest and highest element values.
Cheers.
