It is identified by its address number.
Answer:
INPUT
Explanation:
EXAMPLE PYTHON CODE
_______________________________________________________
INPUT CODE:
_______________________________________________________
foo = input('foo: ')#Have some text printed before the input field
bar = foo
print(bar)
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OUTPUT CODE:
_______________________________________________________
foo: Hello World!
Hello World!
>>> bar
'Hello World!'
>>>foo
'Hello World!'
Answer:
The solution code is written in Java
- public static void checkCommonValues(int arr1[], int arr2[]){
- if(arr1.length < arr2.length){
- for(int i = 0; i < arr1.length; i++){
- for(int j = 0; j < arr2.length; j++){
- if(arr1[i] == arr2[j]){
- System.out.print(arr1[i] + " ");
- }
- }
- }
- }
- else{
- for(int i = 0; i < arr2.length; i++){
- for(int j = 0; j < arr1.length; j++){
- if(arr2[i] == arr1[j]){
- System.out.print(arr2[i] + " ");
- }
- }
- }
- }
- }
Explanation:
The key idea of this method is to repeated get a value from the shorter array to check against the all the values from a longer array. If any comparison result in True, the program shall display the integer.
Based on this idea, an if-else condition is defined (Line 2). Outer loop will traverse through the shorter array (Line 3, 12) and the inner loop will traverse the longer array (Line 4, 13). Within the inner loop, there is another if condition to check if the current value is equal to any value in the longer array, if so, print the common value (Line 5-7, 14-16).
int IsAbundant(int n)
{
int divisorSum = 0;
for (int i = 1; i < n; i++) {
if ((n % i) == 0) {
divisorSum += i;
}
}
return divisorSum > n;
}
int main()
{
int number = 0;
do {
printf("Enter a number (0 to quit): ");
scanf_s("%d", &number);
if (IsAbundant(number)) {
printf("%d is abundant!\n", number);
} else
{
printf("%d is not abundant.\n", number); }
} while (number > 0);
return 0;
}
Answer:
False
Explanation:
Kleene star is a unary operation, we can perform this on a character or set of strings.It means zero or more than zero up to infinite.
It is represented by Vˣ or V+.
For 1, the kleene star will be empty string '∈' or any number of strings.
1ˣ =(∈,1,11,111,1111,11111......)
In question, the empty string '∈' is not present.
