1 answer:
f(n) = n² + 20
f(1) = 1² + 20 = 21
f(2) = 2² + 20 = 24
f(3) = 3² + 20 = 29
f(4) = 4² + 20 = 36
f(5) = 5² + 20 = 45
f(6) = 6² + 20 = 56
a) first three terms
Answer: 21, 24, 29
b) how many < 50
f(5)=45, f(6)=56 so
Answer: 5
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son 27 Creo que espero haberlo hecho bien.
( 30 / 100 ) * (15.40 ) = ( 3 / 10 )* (15.40) = 36.20 / 10 = 3.62$.
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