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lutik1710 [3]
3 years ago
10

How many times goes 15 go into 127

Mathematics
1 answer:
Sauron [17]3 years ago
8 0

Answer:

8 times

Step-by-step explanation:

8*15 = 120

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62-9.817 <br>BTW ITS AN DECIMAL.
Basile [38]
62.000
-9.817
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52.183
5 0
3 years ago
Help me with this please!!!!
spayn [35]

Answer:

y = 2

Step-by-step explanation:

since on a horizontal line which means y axis and the sllope line is on 2

5 0
2 years ago
Hey anyone mind helping out
natulia [17]
Your answer is A :))))
4 0
3 years ago
Read 2 more answers
40 points I'll mark you as BRAINLIEST for the person with the right answers .
Karo-lina-s [1.5K]
9. y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)

10.
group
y=(1/4x^2-3x)+18
undistribute
y=1/4(x^2-12x)+18
take 1/2 of -12 and square it and add neg and pos isndie
y=1/4(x^2-12x+36-36)+18
factor
y=1/4((x-6)^2-36)+18
expand
y=1/4(x-6)^2-9+18
y=1/4(x-6)^2+9
get to form (x-h)^2=4p(y-k)
minus 9 both sides and times 4
(x-6)^2=4(y-9)
(x-6)^2=4(1)(y-9)
so 1>0 so opens up and focus is 1 above vertex
vertex is (6,9)
so focus i (6,10)





11.
y=(-1/6x^2+7x)-80
y=(-1/6)(x^2-42x)-80
take 1/2 of linear coefient and squer it and add negative and positive inside
-42/2=-21, (-21)^2=441
y=(-1/6)(x^2-42+441-441)-80
factor perfect square the square
y=(-1/6)((x-21)^2-411)-80
expand
y=(-1/6)(x-21)^2+73.5-80
y=(-1/6)(x-21)^2-6.5
add 6.5 to both sid
y+6.5=(-1/6)(x-21)^2
times both sides by -6
-6(y+6.5)=(x-21)^2
(x-21)^2=-6(y+6.5)
(y-21)^2=4(-3/2)(y-(-6.5))
vertex is
-3/2<0 so directix is above
it is -3/2 or 1.5 units above the vertex
up is y so
-6.5+1.5=-5
the directix is y=-5




11.
in form (y-1)^2=4p(x+3)
opens left or right
(y-1)^2=4(4)(x+3)
vertex is (-3,1)
4>0 so opens right
dirextix is to left
it is 4 units to left
(-3,1)
left right is x
4 left of -3 is -4-3=7
x=-7 is da directix
3 0
3 years ago
How do you solve 3^(4x) = 3^(5-x)?
trasher [3.6K]
3^(4x) = 3^(5 - x)
4x = 5 - x
4x + x = 5
5x = 5
x = 5/5 = 1
x = 1
3 0
3 years ago
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