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2 years ago

Find the missing lengths in the figure below. Then, find the perimeter of the figure. All measurements are in inches.

Mathematics

1 answer:

dlinn [17]2 years ago

6 0

Answer:

A = 1.83 inches

B = 0.62 inches

C = 1.82 inches

D and E = 2.71 inches

Step-by-step explanation:

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A rectangle is dilated by a scale factor of 4.

Elanso [62]

A) The new dimensions would be 32cm by 12cm.
B) This is an enlargement.

To find the new dimensions, multiply the original dimensions by the scale factor. 8*4=32 and 3*4=12.

This is an enlargement because the copy is larger than the original.

7 0

3 years ago

Chris rode his bike along the same route everyday for 60 days. He logged that he had gone exactly 127.8 miles. How many miles di

blagie [28]

127.8/60 = 2.13

Your answer would be that Chris rode his bike 2.13 Miles per day

5 0

3 years ago

What is the distance between the points (-12, 11) and (-18, 17), to the<br> nearest tenth? *

Basile [38]

Answer:

8.5 units

Step-by-step explanation:

The distance between two points is given by

$d=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Taking points (-12, 11) and (-18, 17) as the first and second points respectively then

$d=\sqrt{(-18--12)^{2}+(17-11)^{2}}$

$d=\sqrt {36+36}$

d=8.48528137423857 units

Rounded off to nearest tenths

d=8.5 units

6 0

3 years ago

Cos (A+B) =1/5<br>COS (A-B) = 3/5<br>Then find tan (A-B)

Soloha48 [4]

Answer:

tan (A-B) = ± 4/3

Step-by-step explanation:

COS (A-B) = 3/5

COS² (A-B) = (3/5)² = 9/25 = 1 - sin² (A-B)

sin² (A-B) = 1 - 9/25 = 16/25

sin (A-B) = ± 4/5

tan (A-B) = sin (A-B) / cos (A-B) = (± 4/5) / (3/5) = ± 4/3

4 0

3 years ago

A savings and loan association needs information concerning the checking account balances of its local customers. A random sampl

Marina86 [1]

Answer:

The 99% confidence interval for the true mean checking account balance for local customers is ($439.29, $888.99).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 3.0123

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 3.0123\frac{279.29}{\sqrt{14}} = 224.85$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 664.14 - 224.85 = $439.29

The upper end of the interval is the sample mean added to M. So it is 664.14 + 224.85 = $888.99.

The 99% confidence interval for the true mean checking account balance for local customers is ($439.29, $888.99).

4 0

3 years ago