Answer:
The horizontal distance between the parking lot and the launch site is 470 meters
Step-by-step explanation:
Let
x-----> the horizontal distance between the parking lot and the launch site
we know that
The tangent of angle of 12 degrees is equal to divide the altitude of 100 meters by the horizontal distance
so
tan(12°)=100/x
Solve for x
x=100/tan(12°)=470 meters
Answer:
1. 4
2. 16
3. 9
Step-by-step explanation:
Completing the square requires a quadratic in
form. Once in this form, calculate
.
1. ![(\frac{b}{2})^2=(\frac{-4}{2})^2=4](https://tex.z-dn.net/?f=%28%5Cfrac%7Bb%7D%7B2%7D%29%5E2%3D%28%5Cfrac%7B-4%7D%7B2%7D%29%5E2%3D4)
2. ![(\frac{b}{2})^2=(\frac{-8}{2})^2=16](https://tex.z-dn.net/?f=%28%5Cfrac%7Bb%7D%7B2%7D%29%5E2%3D%28%5Cfrac%7B-8%7D%7B2%7D%29%5E2%3D16)
3. Requires you divide everything by 3 first.
![\frac{3x^2+18x}{3} =\frac{249}{3} \\x^2+6x=81](https://tex.z-dn.net/?f=%5Cfrac%7B3x%5E2%2B18x%7D%7B3%7D%20%3D%5Cfrac%7B249%7D%7B3%7D%20%5C%5Cx%5E2%2B6x%3D81)
![(\frac{b}{2})^2=(\frac{6}{2})^2=9](https://tex.z-dn.net/?f=%28%5Cfrac%7Bb%7D%7B2%7D%29%5E2%3D%28%5Cfrac%7B6%7D%7B2%7D%29%5E2%3D9)
As we could "drag" these together, we could then do it the easy way.
56
+56
+56
-------
168
------------------------
Or we could also do the following:
56
![*](https://tex.z-dn.net/?f=%2A)
3:
6
![*](https://tex.z-dn.net/?f=%2A)
3= 18.
Carry the one.
5
![*](https://tex.z-dn.net/?f=%2A)
3 = 15+1 (which was carried). = 16
(16+8) =
168
Wait what?? If you are talking about how much it could have caught it's 0 I guess
Answer:
1 5/12
Step-by-step explanation:
12 1/3 - 10 11/12
We need to get a common denominator of 12
12 1/3 * 4/4 - 10 11/12
12 4/12 - 10 11/12
We need to borrow from the 12 (the whole number) because the 2nd fraction is bigger than the first
12 becomes 11 and the 1 becomes 12/12
11+ (12/12 + 4/12) - 10 11/12
11 16/12 - 10 11/12
Subtract the whole numbers
11-10 =1
Subtract the fractions
16/12 - 11 /12 = 5 /12
We are left with 1 5/12