All categories

3 years ago

I need help with these problems hdndjnfmsmf

Mathematics

1 answer:

maria [59]3 years ago

4 0

The answer is Value of H=2

You might be interested in

RectangleABCD has vertices at A(– 3, 1),B(– 2, – 1),C(2, 1), andD(1, 3). What is the area, in square units, of this rectangle? A

Anna [14]

Answer:

Option A. $10\ units^{2}$

Step-by-step explanation:

we know that

The area of the rectangle is equal to

A=LW

where

L is the length of rectangle

W is the width of rectangle

we have

$A(-3,1),B(-2,-1),C(2,1),D(1,3)$

Plot the vertices

see the attached figure

L=AD=BC

W=AB=DC

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AD

$A(-3,1),D(1,3)$

substitute in the formula

$AD=\sqrt{(3-1)^{2}+(1+3)^{2}}$

$AD=\sqrt{(2)^{2}+(4)^{2}}$

$AD=\sqrt{20}$

$AD=2\sqrt{5}\ units$

Find the distance AB

$A(-3,1),B(-2,-1)$

substitute in the formula

$AB=\sqrt{(-1-1)^{2}+(-2+3)^{2}}$

$AB=\sqrt{(-2)^{2}+(1)^{2}}$

$AB=\sqrt{5}$

$AB=\sqrt{5}\ units$

Find the area

$A=(2\sqrt{5})*(\sqrt{5})=10\ units^{2}$

4 0

3 years ago

the figure below is made of rectangles what is the perimeter of the figure below? note that not all the side lengths are labeled

Anit [1.1K]

The perimeter is 30cm

5 0

3 years ago

Solve the problem. The half-life of plutonium-234 is 9 hours. If 50 milligrams is present now, how much will be present in 6 day

MaRussiya [10]

Answer:

4) 0.001

Step-by-step explanation:

The amount (a) present in h hours is ...

a(h) = (initial value)×(1/2)^(h/(half-life))

6 days is 6×24 hours, so the amount remaining is ...

a(6×24) = 50×(1/2)^(6×24/9) = 50/2^16 ≈ 0.001 . . . . milligrams

3 0

3 years ago

Simplify (a + 2b +30) - (40+36-5a)

Crazy boy [7]

Step-by-step explanation:

(a+2b+30)-(40+36-5a)
a+2b+30-40-36+5a
6a+2b-46

hope it helps.

3 0

3 years ago

Can someone pls show how to do this is with explanation

Keith_Richards [23]

1m = 100 cm
0.05 m = 5cm
1 km = 10000 cm
0.00005 km = 5 cm
Yes they are equal

(Mark me the brainliest if this has helped!)

4 0

2 years ago