Graph the function f.

Round off 9.999 to the nearest 10

dlinn [17]

Answer:

the answer is 10 you round up a nine it keeps going to the end

6 0

2 years ago

2. After the relay race, Larry, Curly, and Moe went to the

jarptica [38.1K]

Using proportions, it is found that each of the 6 people got $0.5.

<h3>Proportions:</h3>

This question is solved by <em>proportions</em>, using a rule of three.

$3.00 is shared between 6 people, which are Larry, Curly, Moe, Alvin, Simon and Theodore. How much did each people(1 person) get?

The <em>rule of three</em> is:

$3.00 - 6 people

$x - 1 person

Applying cross multiplication:

$6x = 3$

$x = \frac{3}{6}$

$x = 0.5$

Each of the 6 people got $0.5.

To learn more about proportions, you can take a look at brainly.com/question/24372153

7 0

2 years ago

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0

3 years ago

Is 21,063 divisible by three? If it is, write a number as a product of three and another factor if not, explain

Zarrin [17]

Twenty-one thousand and sixty-three divided by three is 7021

First, take any number (for this example it will be 492) and add together each digit in the number (4+9+2 = 15). Then take that sum (15) and determine if it is divisible by 3. The original number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9).If a number is a multiplication of 3 consecutive numbers then that number is always divisible by 3. This is useful for when the number takes the form of (n * (n - 1)*(n + 1))Example: 492 (The original number). 4 + 9 + 2 = 15 (Add each individual digit together). 15 is divisible by 3 at which point we can stop. Alternatively we can continue using the same method if the number is still too large: 1 + 5 = 6 (Add each individual digit together). 6 ÷ 3 = 2 (Check to see if the number received is divisible by 3). 492 ÷ 3 = 164 (If the number obtained by using the rule is divisible by 3, then the whole number is divisible by 3)

4 0

3 years ago

If the base ten blocks shown are to be divided into 13 equal groups. What should be done

In-s [12.5K]

Answer:

is this the right question please??

8 0

3 years ago

Graph the function f.​

Graph the function f.