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Lapatulllka [165]
3 years ago
7

Suppose Marlie only paid interest during her 4 years in school and the six-month grace period. What will she pay now in interest

over the term of the loan
Mathematics
1 answer:
dmitriy555 [2]3 years ago
7 0

Answer: interest = $ 3,629.34

Step-by-step explanation:

Complete question

(Marlie will be starting college next year, federal unsubsidized student loan in the amount of $18,800 at 4.29%. She knows that during this non-payment time, interest will accrue at 4.29%. Suppose Marlie only paid the interest during her four years in school and the six-month grace period. What will she now pay in interest over the term of the loan.)

This question relates to interest over a single period of time and since it's not compounded, we use formula for simple interest to calculate the interest accrued.

Data;

P = $18,800

R = 4.29% = 0.0429

T = 4.5 years

S.I = ?

S.I = PRT

S.I = 18,800 * 0.0429 * 4.5

S.I = $3,629.34

Therefore she'll need to pay $3,629.34 as interest accrued.

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*Given

Money of Phoebe            - 3 times as much as Andy

Money of Andy                - 2 times as much as Polly

Total money of Phoebe,  - £270

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Let

B - Phoebe's money

A - Andy's money

L - Polly's money

1. The money of the Phoebe, Andy, and Polly, when added together would total £270. Thus,

                 B + A + L  = £270                     (EQUATION 1)

2. Phoebe has three times as much money as Andy and this is expressed as

 

                 B = 3A

3. Andy has twice as much money as Polly and this is expressed as

                 A = 2L                           (EQUATION 2)

4. This means that Phoebe has ____ as much money as Polly,

                B = 3A

                B = 3 x (2L)

                B = 6L                            (EQUATION 3)

This step allows us to eliminate the variables B and A in EQUATION 1 by expressing the equation in terms of Polly's money only.

5. Substituting B with 6L, and A with 2L, EQUATION 1 becomes,

                 6L + 2L + L = £270

                               9L = £270

                                 L = £30

So, Polly has £30.

6. Substituting L into EQUATIONS 2 and 3 would give us the values for Andy's money and Phoebe's money, respectively.

                 A = 2L                          

                 A = 2(£30)

                 A = £60

Andy has £60

                 B = 6L                        

                 B = 6(£30)

                 B = £180

Phoebe has £180

Therefore, Polly's money is £30, Andy's is £60, and Phoebe's is £180.

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