Use the distance formula: D=sqrt((x2-x1)^2+(y2-y1)^2)
Plug in:
D=sqrt((9-8)^2+(-1-2)^2)
D=sqrt(1^2+(-3)^2)
D=sqrt(1+9)
D=sqrt(10)
So the distance is about 3.16 units
Hope this helped!
R + b = 21
2b = r
now we sub eq 2 into eq 1
r + b = 21
2b + b = 21
3b = 21
b = 21/3
b = 7
2b = r
2(7) = r
14 = r
so there are 7 bluejays (b) and 14 robins (r)...for a total of 21
B because if there are 10 large dogs and that is two times the number of small dogs than there are half as many small dogs as big doge which would mean the equation is D=1/2(10)+10.
Answer:
The best estimate of the probability of getting a green marble from this bag of 50 marbles is 1/3.
Step-by-step explanation:
Andre gets 1 green marble out of 4 trials.
For Andre, the probability of getting 1 green marble is 1/4.
Jada gets 5 green marbles out of 12 trials.
For Jada, the probability of getting 1 green marble is 5/12.
Noah gets 3 green marbles out of 9 trials.
For Noah, the probability of getting 1 green marble is 3/9.
Hence, the best estimate of the probability of getting a green marble from this bag = (1/4 + 5/12 + 3/9)/3 = [(9 + 15 + 12)/36]/3 = 1/3.
