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Zielflug [23.3K]
3 years ago
12

Given the replacement set {2, 3, 4, 5}, solve 4x – 3 = 2x + 5. GIVING 20 POINTS !!

Mathematics
1 answer:
Advocard [28]3 years ago
7 0

Answer:

x=4

Step-by-step explanation:

4x - 3 = 2x + 5

4x - 2x = 5 + 3

2x = 8

x = 8/2

x = 4

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Solve the equations<br> 7 x = 21<br> 2/3 = 5/6
S_A_V [24]

Answer:

x = 3??

Step-by-step explanation:

4 0
3 years ago
4) (Assume AR is tangent)<br>Given: AR 12<br>SR - 7.7<br>Find: cs (Round to nearest tenth.)​
andreev551 [17]

The length of CS is 11.0

Explanation:

Given that the length of the tangent AR is 12

The length of SR is 7.7

To find: The length of CS

The<u> tangent secant theorem</u> states that "if a tangent and a secant are drawn from an external point to a circle, then the square of the measure of the tangent is equal to the product of the measures of the secant’s external part and the entire secant."

Applying the tangent secant theorem, we have,

AR^2=SR\times RC

Rewriting the above equation, we get,

AR^2=SR(SR+SC)

Substituting the values, we get,

12^2=7.7(7.7+CS)

Simplifying, we have,

144=59.29+7.7CS

Subtracting both sides by 59.29, we get,

84.71=7.7CS

Dividing both sides by 7.7, we have,

11.0013=CS

Rounding off to the nearest tenth, we get,

11.0=CS

Thus, the length of CS is 11.0

6 0
3 years ago
What's the word phrase for 2(5-n)
solmaris [256]
I would say: 2 times 5 less a number.
5 0
4 years ago
The length of a rectangle is 3 more inches than the width. Find the length and width of the rectangle is the perimeter of the re
n200080 [17]

Part A:

Let the width of the rectangle be = x inches

As given, the length of a rectangle is 3 more inches than the width so let the length of the rectangle be = x+3 inches

Perimeter is given as = 54 inches

Perimeter = 2(l+b)

Equation becomes:

2(x+3+x)=54

2(2x+3)=54

Part B:

Solving the equation we get

4x+6=54

4x=54-6

4x=48

x=12

Hence, the width of the rectangle is 12 inches

Length = x+3 = 12+3 = 15 inches

Hence, length of the rectangle is 15 inches.


5 0
4 years ago
How do you solve 2x^2 - 7x -5= 0 in quadratic form?
lesantik [10]

Answer:

Once the equation is in standard form, factor the quadratic expression. 2x2 + 7x + 3 = 0 (2x + 1)(x + 3) = 0. Using the Zero Product Property set ...

2x2 + 7x = -3

2x2 + 7x + 3 = 0

Once the equation is in standard form, factor the quadratic expression.

2x2 + 7x + 3 = 0

(2x + 1)(x + 3) = 0

Using the Zero Product Property set each factor equal to 0 and solve for x.

2x + 1 = 0  

2x + 1 - 1 = 0 - 1 x + 3 = 0

2x = -1 x + 3 - 3 = 0 - 3

2x 2 = -1 2 x = -3

x = -1 2  

The solutions to the equation are -1 2 and -3.

7 0
3 years ago
Read 2 more answers
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