Question

What is the distance between (2,-6) and (-4,8)

Answer 1

The formula for distance is:

$d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

Use this formula to solve your problem where:

1 = (2, -6)

2 = (-4, 8)

$d = \sqrt{(-4 - 2)^2 + (8 + 6)^2}\\\\d = \sqrt{(-6)^2 + (14)^2}\\\\d = \sqrt{36 + 196}\\\\d = \sqrt{232} = 15.232$

The distance between (2, -6) and (-4, 8) is 15.232 units.