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Vlad1618 [11]
3 years ago
14

after every 9th visit to a restaurant you receive a free beverage after every 12th visit you receive a free appetizer if you vis

it the restaurant 100 times on which visit will you receive a fee beverage and a free appetizer at which visit will you first receive a free beverage and a free appetizer
Mathematics
1 answer:
Fed [463]3 years ago
5 0
100th visit this is easy
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Find the area of this shape<br> giving brainliest please help
pogonyaev
ANSWER: ⇒ 366.19cm²

I hope this helps you :)

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2 years ago
A copy waa made of sallys photograph. The copy resized the photograph so that it measured 4 inches wide by 8 inches long. If the
Rashid [163]

Answer:

48

Step-by-step explanation:


5 0
3 years ago
Please helpppp!!! Find the area of the irregular figure
OverLord2011 [107]

Answer:

The area of the figure is 143 sq in

Step-by-step explanation:

10 in * 7 in = 70 sq in

12 in * 4 in = 48 sq in

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3 0
3 years ago
Can somebody help me on 23 and 24, it’s geometry
Luda [366]

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Step-by-step explanation:

As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE

<u>Question number 23:</u>

Given

DS = 3x+10

SE = 6x-2

As the two segments are equal:

DS = SE\\3x+10 = 6x-2

Subtracting 10 from both sides

3x+10-10 = 6x-2-10\\3x = 6x-12

subtracting 6x from both sides

3x -6x = 6x-6x-12\\-3x = -12

Dividing both sides by -3

\frac{-3x}{-3} = \frac{-12}{-3}\\x = 4

Now

DS = 3x+10\\= 3(4)+10\\= 12+10\\=22

And

SE = 6x-2\\= 6(4)-2\\= 24 - 2\\=22\\DE = DS+SE\\= 22+22\\=44

<u>Question No 24:</u>

Given

DS = x+3

DE = 56

We know that:

DS = \frac{1}{2}DE\\x+3 = \frac{56}{2}\\x + 3 = 28\\x = 28-3\\x = 25

So

DS = 25+3 = 28

As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

4 0
3 years ago
What is the reliability of a two-component product if the components are in parallel, with individual reliabilities of 0.95, and
user100 [1]

The reliability of a two-component product if the components are in parallel is 0.99.

In this question,

The probability of failure-free operation of a system with several parallel elements is always higher than that of the best element in the system. Reliability can be increased if the same function is done by two or more elements arranged in parallel.

A system contains two components that are arranged in parallel, they are 0.95 and 0.80.

Therefore the system reliability can be calculated as follows

⇒ 1 - ( 1 - 0.95 ) × ( 1 - 0.80 )

⇒ 1 - (0.05 × 0.20)

⇒ 1 - 0.01

⇒ 0.99

Hence we can conclude that the reliability of a two-component product if the components are in parallel is 0.99.

Learn more about reliability of components here

brainly.com/question/20314118

#SPJ4

6 0
1 year ago
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