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Ira Lisetskai [31]
3 years ago
11

Answer question 1 and 2 on the champions challenge? it really matters

Mathematics
1 answer:
babunello [35]3 years ago
8 0
If length = a, width = b
if double both a and b will double its area?
area of a rectangle is ab
if double both a and b then the area is (2a)(2b) = 4ab (then peter is wrong because the area will be 4 times not double)
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How can I solve -4x+y=29
vlada-n [284]

Answer:

Step-by-step explanation:

What variable are you solving for?

-4x+y=29

y=29-(-4x)

y=29+4x

y=4x+29

----------------

-4x=29-y

-4x=-y+29

x=1/4y+29/-4

y=1/4y-29/4

7 0
3 years ago
Read 2 more answers
A thread is being pulled off a spool at the rate of 40 cm per second. Find the radius of the spool
murzikaleks [220]

Answer:

r = 0.0424 cm (3sf)

Step-by-step explanation:

it makes 150 rev/sec

1 revolution = 1 circumference = 2pi*r

so every second the spool goes through 2*pi*r*150 of distance

we know that the rate of pulling is 40cm/sec

so 2pi*r*150 = 40

r = 40/(2pi*150), which is 0.04244131816 cm.

check: Circumference is 2pi*r = 0.2666

now multiply by 150rev/sec = 40 cm/sec

3 0
2 years ago
Given (21,7) and (x,<br> 1), find all x such that the distance between these two points is 17.
Dmitriy789 [7]

Answer:

21+/-sqrt(253)=x

So one value for x is 21+sqrt(253)

and another is 21-sqrt(253)

Problem:

Given (21,7) and (x,1), find all x such that the distance between these two points is 17.

Step-by-step explanation:

Change in x is x-21

Change in y is 7-1=6

distance^2=(change in x)^2+(change in y)^2

17^2=(x-21)^2+(6)^2

289=(x-21)^2+36

Subtract 36 on both sides:

289-36=(x-21)^2

253=(x-21)^2

Take square root of both sides:

+/-sqrt(253)=x-21

Add 21 on both sides:

21+/-sqrt(253)=x

6 0
3 years ago
What is the square roots of 9
Lyrx [107]

Answer:

(x-3) and (x+3) I think

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
F
galina1969 [7]
It’s F because I took the test
8 0
3 years ago
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