Answer: at the equator the normal force will be 3.4N less and at the North Pole = 980N
Explanation:
So, we will start the Calculation by considering the equation below;
Fnet = F(g) - F(N); where Fnet = mv^2/ r.
Hence, F(g) - F(N) = mv^2/ r -------------(1).
Making F(N) the subject of the formula, we have;
F(N) = Gm1m2/r^2 - mv^2/r.
Thus, we have;
Gm1m2/r^2 = 6.68 × 10^-11 × (5.98 × 20^24) × 100/ 6.38 × 10^6 = 980N.
Also, we have;
mv^2/r = m4π^2r/T^2.
100 × 6.38 ×10^6 × 4π^2/(24 × 3600)^2 = 3.4N
Therefore, at the equator the normal force will be 3.4N less and at the North Pole = 980N.
Explanation:
One cycle of the moon phases last for almost around 29 and a half days or 29.5 days .
There are four phases of the moon .
The average number of days between 4 intermediate phases of moon is approximately 7.4 days , however between full , waning/waxing gibbous , waning / waxing crescent,and new moon is around 3.5 days .
Answer:
The dead sea is shrinking, and as it recedes, the fresh water aquifers along the perimeter of the lake are receding along with it. As this fresh water diffuses into salt deposits beneath the surface of the shoreline, the water slowly dissolves the deposits until the earth above collapses without warning.