Answer:
He has 45 kids now.
Step-by-step explanation:
Answer:
-11f +15
Step-by-step explanation:
-f-5(2f-3)
Distribute
-f -10f +15
Combine like terms
-11f +15
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
All angles in triangle inside add up to 180
so
the angles are y, 79,37
therefor
y+79+37=180
solvde for y
y+79+37=180
add
y+116=180
subtract 116 from ot hsides
y=64
angle y=64 degrees
Answer:
37/40
Step-by-step explanation:
There are 3 numbers between 1 and 40 that are a multiple of 13: 13,26,39.
So, your probability should be 40-3/40, = 37/40.
