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REY [17]
3 years ago
10

What is 32751 divided by 9

Mathematics
1 answer:
Olegator [25]3 years ago
5 0

Answer:

3639

Step-by-step explanation:

Hope this helps

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Simplify 10(N + 3).<br><br> 10N + 30<br> 10N + 13<br> 10N + 3
In-s [12.5K]
10(N + 3)

= 10N + 30

Hence, the answer is A.
3 0
3 years ago
Read 2 more answers
4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia
Ad libitum [116K]

The <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its <em>standard</em> form from the coordinates of the foci and a <em>general</em> equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the <em>general</em> equation of the circle into its <em>standard</em> form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0​

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (<em>semi-major</em> distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

#SPJ1

5 0
2 years ago
Item 8 Solve for x. Use the quadratic formula. 2x2−5x−9=0 Enter the solutions, in simplified radical form, in the boxes.
Lubov Fominskaja [6]

Answer:

5+√97/4

Also 5-√97/4

Step-by-step explanation:

The Quadratic formula is x=-b+-√b^2-4ac/2a

This means that we should plug the values for A B AND C into the formula

We can work out that

<u><em>A = 2</em></u>

<u><em>B=-5</em></u>

<u><em>C=-9</em></u>

Once we have put these into the formula we get

5+√97/4 (all over 4) aka 3.71

Also 5-√97/4 (all over 4) aka -1.21

7 0
3 years ago
Read 2 more answers
Can anyone help me with this? no links
Tatiana [17]

Answer:

Step-by-step explanation:

as you see the top "moves" like

2,4,6,8, and next will be 10

the bottom adds 3 to the previos answer

5,8,11,14,  next will be 15

5th card is 10/15

4 0
2 years ago
I need help! PLEASE HELPP PLEASE HELP!!!
DanielleElmas [232]

Answer:

Part 1: 31x+25=180

part 2: x=5

Step-by-step explanation:

there are 180° on a straight line, which is the base/ bottom line of the traingle (indicated by the arrow on the end).

so, 180-151= 29

29° is the third angle on the traingle.

now, there are 180° in a triangle, therefore to find an equation for x:

29+20x-3+11x-1= 180 (adding up all the angles and making it equal to 180°)

now simplify this equation to get:

31x+25=180 (PART 1)

to find x simply solve the equation:

31x=180-25

31x= 155

x= 155/31

x=5 (PART 2)

4 0
3 years ago
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