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REY [17]
3 years ago
10

What is 32751 divided by 9

Mathematics
1 answer:
Olegator [25]3 years ago
5 0

Answer:

3639

Step-by-step explanation:

Hope this helps

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At a certain school,5/9 of the students are boys. Today, 2/3 of the boys brought their lunch. What fraction of the students are
Elodia [21]
5/6 of the boys brought their lunch.



In order to determine the answer you need to divide 5/9 by 2/3 in which will give you 5/6.
4 0
3 years ago
leila and jo are two of the partners in a business.leila makes $3 in profits every $4 that jo makes.if jo makes $60 profit on th
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3/4=x/60 so you divide 60 by 4 and get 15x3=45/60
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Lois and Clark own a company that sells wagons. The amount they pay each of their sales employees (in dollars) is given by the e
ira [324]
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4 0
3 years ago
Consider the following three equations:
KengaRu [80]

Answer:

1.

y = 20(11) + 300 = 520

y = 5(11)(11) = 605    

y = 10(1.4)^11 = 404.96

hence the quadratic formula - y = 5x^2 has the largest y-value

2.

y = 20 (14) + 300 = 580

y = 5 (14) (14) = 980

y = 10(1.4)^ 14 = 1111.20   >    this is greater than both equations above

14 is the smallest value of x for which the value of the exponential equation is greater than the values of both the linear and quadratic functions

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
A<br> Find tan a.<br> r<br> √5,-√7)<br> ✓[?<br> Enter
Virty [35]

Answer:

tan(\alpha)=-\frac{\sqrt{35}}{5}

Step-by-step explanation:

Tan can be defined as: \frac{sin(\theta)}{cos(\theta)} as it simplifies to opposite/adjacent. If you know a bit about the unit circle, you'll know that the x-coordinate is going to be cos(theta) and the y-coordinate is going to be sin(theta). Since the sin(theta) is defined as opposite/hypotenuse, and the hypotenuse = 1, so sin(theta) is defined as the opposite side, which is the y-axis. Same thing goes for cos(theta), except the adjacent side is the x-axis.

Using this we can define tan

sin(\alpha)=-\sqrt{7}\\cos(\alpha)=\sqrt{5}\\\\tan(\alpha)=-\frac{\sqrt{7}}{\sqrt{5}} * \frac{\sqrt{5}}{\sqrt{5}}\\tan(\alpha)=-\frac{\sqrt{7*5}}{5}\\tan(\alpha)=-\frac{\sqrt{35}}{5}\\

8 0
2 years ago
Read 2 more answers
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