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3 years ago

5/7 = -x/8 i dont undstant this, if someone could help me it would be greatly apprecaited

2 answers:

7 0

You can use cross-products to solve this problem. For instance, this expression would be written as 5(8)= 7(-x), or 40= -7x. What you'd do then is simplify the expression by dividing both sides of the equation by the coefficient of x, such that you'd isolate x and have the value of x.

Whitepunk [10]3 years ago

4 0

5/7 = -x/8

First: What you would do is cross multiply. You would multiply 7 and -x, then 8 and 5.
Your equation should then look like: 40= -7x
Next: You would divide each side by -7 so you can get your x alone.
You would get: x= -5.71... < That would be your answer

HOPE THIS HELPS! ^_^

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3 years ago

Marya wants to factor the polynomial 36x3 – 22x2 – 144x. Which term can she add to the polynomial that would not change its grea

Dafna11 [192]

Answer:

-50xy and -40x²

Step-by-step explanation:

1) Common factor of the letters: x, x², and x³.

It is the common letter with the lowest exponent: x

2) Common factors of the coefficients (numbers): 36, 22, and 144

i) prime factors of 36: 36 = 2² × 3²

ii) prime factors of 22: 22 = 2 × 11

iii) prime factors of 144: 2⁴ × 3²

iv) Greatest common factor: the repeated number raised to the lowest power: 2.

3) Therefore, the greatest common factor of the terms 36x³ - 22x² - 144x is 2x

4) Any number that has 2x as a factor will not change this common factor.

5) Factors of the choices:

i) –11: 2x is not a factor of - 11, therefore this does not apply

ii) –50xy: 2x is a factor, since - 50xy / (2x) = - 25y, therefore this applies.

iii) –40x²: 2x is a factor, since - 40x² / (2x) = -20x, therefore this applies

iv) 24: 2x is not factor of 24, therefore this does not apply

v) 10y: 2x is not a factor of 10y, therefore this does not apply

4 0

3 years ago

Read 2 more answers

Find the particular solution to y ' = 4sin(x) given the general solution is y = c - 4cos(x) and the initial condition y of pi ov

Lana71 [14]

The general solutions always have some additive/multiplicative constant, that you must fix in the particular solution.

In order to do so, you need to impose that the particular solution passes through a certain point. In your case, you have

$y(x) = c-4\cos(x)$

and you want

$y\left(\dfrac{\pi}{2}\right) = 2$

Put everything together, and you have

$y\left(\dfrac{\pi}{2}\right) = c-4\cos\left(\dfrac{\pi}{2}\right) = c = 2$

Since the cosine is zero in the chosen point. So, we've fixed the value of the constant, and the particular solution is found:

$y(x) = 2-4\cos(x)$

4 0

3 years ago

Solve each system by substitution

xeze [42]

Answer:

x=2,y=5

Step-by-step explanation:

y=8x-11 ----(1)

y=-7x+19----(2)

Replace (1) in (2)

8x-11 =-7x+19

8x+7x=19+11

15x =30

x =30÷2

x =2

If x=2,then replace x=2 in (1)

y=8(2)-11

y=16-11

y=5

8 0

3 years ago