The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327
<h3>How to determine the product of the numbers?</h3>
The numbers are given as
853 and 59
By using the standard algorithm i.e. the partial product method, we have the following equation
853 * 59 = 853 * (50 + 9)
Open the bracket
So, we have
853 * 59 = 853 * 50 + 853 * 9
Evaluate the products
So, we have
853 * 59 = 42650 + 7677
The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650
Next, we evaluate the sum
853 * 59 = 50327
This means that the final product is 50327
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Ok so easy peasy
remember that when divide or multiply by negative, reverse the inequality symbol example
2>3 times -1=
-2<-3 so
-150x<u>></u>-2400
divide both sides by -150
flip sign
<u />x<u><</u>16
-336<u>></u>-21y
divide both sides by -21
flip sign
16<u><</u>y
they seem to have the same solution
x=y<u>></u>16
Answer:
<h2>$ 22200 in higher yielding bank and $ 44400 in lower yielding bank</h2>
Step-by-step explanation:
Jolene invests in two bank accounts. The first account gives a 4% interest per year and the second bank gives a 10% interest rate per year.
She puts twice as much in the lower yielding bank account. Let us denote the amount put in high yielding bank account by 
. Lower yielding bank account will have 
.
Interest from lower yielding bank = 
Interest from higher yielding bank = 
Total Interest per year = $ 3996 = 
∴ Jolene invested $ 22200 in higher yielding bank and $ 44400 in lower yielding bank.
The monthly payment for the new car is; Choice A; $279. 03
<h3>Percentages</h3>
After the down payment of 30% and financing the 8% TT&L is made; it follows that;
The rest of the payment is;
Hence, $8,897 is the payment made over the course of the duration at a finance rate of 3.16%.
Ultimately, the monthly payment is; $8,897 × 0.0316 = $279.03
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If B is the midpoint of AC, then |AB| = |AC|.
|AB| = 3x + 2
|BC| = 5x - 10
Therefore we have the equation:
3x + 2 = 5x - 10 |subtract 2 from both sides
3x = 5x - 12 |subtract 5x from both sides
-2x = -12 |divide both sides by (-2)
x = 6
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