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AVprozaik [17]
3 years ago
7

How do you solve for x? -12+7=-5(x+2)

Mathematics
2 answers:
dusya [7]3 years ago
7 0
-5= -5x-10

Plus 10 from both sides

5=-5x
X = -1
nordsb [41]3 years ago
7 0

To solve this you would have to use a reverse PEMDAS- it would be easy to start out simplifying the equation so -12 + 7 would be -5. (-5 = -5 (x+2))Next you can try to get rid of the -5 outside the parentheses by adding 5 to both sides, now making the problem 0 = x + 2. So, subtract the two from both sides and you are left with your answer -2= x

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What will be the linear equation for the shown table?<br><br>​
vladimir1956 [14]

Answer:

y=2x+5

Step-by-step explanation:

To find a linear equation you must find the slope and y intercept to create an equation in y=mx+b form (slope-intercept form)

So slope is = y2-y1 / x2-x1 [2 and 1 are subscripts] so 11-7/3-1 so m=4/2 = 2

Slope = 2, now find b

So using y = mx + b, substitute what you know so 7 = 2(1) + b so b=7-2 = 5

Put it all together y = 2x + 5

3 0
2 years ago
What is the value of a 3 - b 2 for a = 3 and b = ? A. 8 B. 8 3/4 26 3/4 26
ArbitrLikvidat [17]
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6 0
3 years ago
Three less than twice a number is 15.
inessss [21]

Answer:

3-2x=15

Step-by-step explanation:

add 3 to both sides makes -2x=18. divide -2 from both side gets the answer x=-9, so the answer is C, -9

5 0
2 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
2 years ago
Read 2 more answers
I need help with this question
Wittaler [7]

Answer:

A=W, B=X, C=Y, D=Z, AB=WX, BC=XY, CD=YZ, AD=WZ

(The second answer down)

Step-by-step explanation:

3 0
2 years ago
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