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AVprozaik [17]
3 years ago
7

How do you solve for x? -12+7=-5(x+2)

Mathematics
2 answers:
dusya [7]3 years ago
7 0
-5= -5x-10

Plus 10 from both sides

5=-5x
X = -1
nordsb [41]3 years ago
7 0

To solve this you would have to use a reverse PEMDAS- it would be easy to start out simplifying the equation so -12 + 7 would be -5. (-5 = -5 (x+2))Next you can try to get rid of the -5 outside the parentheses by adding 5 to both sides, now making the problem 0 = x + 2. So, subtract the two from both sides and you are left with your answer -2= x

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<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
2 years ago
Consider the system:
Gnom [1K]

Answer:

Step-by-step explanation:

In this problem, we have the following linear equations:

y=3x+5

y=ax+b

We know that a linear equation is an equation for a line. In a system of linear equations, two or more equations work together.

1.  What values for a and b make the system inconsistent?

A system is inconsistent if and only if the lines are parallel in which case the system has no solution. This is illustrated in the first Figure bellow. Two lines are parallel if they share the same slope. So, the system is inconsistent for:

a=3

for any value of b

2. What values for a and b make the system consistent and dependent?

A system is consistent if and only if the lines are the same in which case the system has infinitely many solutions. This is illustrated in the second Figure bellow. So, the system is consistent and dependent for:

a=3 and b=5

8 0
2 years ago
Read 2 more answers
Helphelphelphelphelphelphelphelp
solniwko [45]

Answer:

Step-by-step explanation:

the areas are the same, the outer squares of Q are the ones missing in the center

7 0
1 year ago
ANSWER STAT!! ASAP!! OTHER WORDS THAT RELAT TO THAT!!!
kvasek [131]
I guess its 3.5x (edited) .....
8 0
3 years ago
Read 2 more answers
GEOMETRY!!! 15 PTSSSSS
ss7ja [257]

Answer:

23) option c

    JL ≈ 9.3

25) option c

      y ≈ 9.6

Step-by-step explanation:

<h3>25)</h3>

Given in the question that,

cos(21°) = 9 / y

y = 9/cos(21°)

y = 9.64

y ≈ 9.6(nearest tenth)

<h3>23)</h3>

Given in the question that the hypotenuse of right angle triangle = 12

To find,

height of the right angle triangle

angle k = 39°

so by using trigonometry identity

cos(39) = opp/hypo

cos(39) = JL / KL

JL = cos(39)(12)

JL = 9.32

JL ≈ 9.3

<h3 />
4 0
3 years ago
Read 2 more answers
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